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Matrix Script

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593 Discussions

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  • yashdeora98294
     + 0 comments

    Here is HackerRank Matrix Script in Python solution - https://programmingoneonone.com/hackerrank-matrix-script-problem-solution-in-python.html

  • poudelmaheshwor1
     + 0 comments

    How is # and % alpha numeric? I do not understand.

  • singhshrajan
     + 1 comment
    import re

def solve(matrix, n, m):
    string = ""
    # Here I use zip which transposes the matrix; that means it converts rows into columns
    # You can also use numpy
    # Using nested loops is not ideal in Python, so zip is used to avoid that
    matrix_T = list(zip(*matrix))
  
    for i in matrix_T:
        string += "".join(list(i))
    
    clear = re.sub(r'(?<=[a-zA-Z0-9_])[!@#$%&" "]+(?=[a-zA-Z0-9_])', ' ', string)
    
    print(clear)

  • dbshoy
     + 2 comments

    I am confused about why this is not working. If anyone can help I'll apreceate.

    import math
import os
import random
import re
import sys

if __name__ == '__main__':
    first_multiple_input = input().rstrip().split()

    n = int(first_multiple_input[0])

    m = int(first_multiple_input[1])

    matrix = []

    for _ in range(n):
        matrix_item = input()
        matrix.append(matrix_item)

    text = ''
    for j in range(m):
        for i in range(n):
            if j < len(matrix[i]):
                text += matrix[i][j]
            else:
                text += ' '
    result = ''
    i = 0
    while i < len(text):
        if text[i].isalnum():
            result += text[i]
            i += 1
        elif text[i].isspace():
            result += text[i]
            i += 1
        else:
            next_alnum = i + 1
            while next_alnum < len(text) and not text[next_alnum].isalnum():
                next_alnum += 1
            
            if (i > 0 and text[i-1].isalnum() and 
                next_alnum < len(text) and text[next_alnum].isalnum()):
                result += ' '
                i = next_alnum
            else:
                result += text[i]
                i += 1
    if result.strip() and result.strip()[0] == '#':
        result = result.rstrip() + ' @'
    
    print(result)

  • some_random
     + 1 comment

    Here is a really simple but hopefully readable solution:

    #!/bin/python3

import re
n, m = map(int, input().split())        
matrix = [ input() for _ in range(n) ] 

# a very Pythonic way to transpose and flatten a list of iterables - barely readable but you know what it's doing
transpose = ''.join([c for ls in zip(*matrix) for c in ls])

# Lookaheads and Lookbehinds let us use a simple 'sub' to replace every sandwiched cluster of symbols.
print(re.sub(r"(?<=\w)[!@#$%& ]+(?=\w)", " ", transpose))