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No, it is not, it's actually O(log2(R)), finding the most significant bit is not constant.
O(log2(R))
I was just a bit naive, and didn't see that in my case b = f(R) = log2(R)
b = f(R) = log2(R)
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Maximizing XOR
You are viewing a single comment's thread. Return to all comments →
No, it is not, it's actually
O(log2(R)), finding the most significant bit is not constant.I was just a bit naive, and didn't see that in my case
b = f(R) = log2(R)