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  1. Prepare
  2. Python
  3. Strings
  4. Merge the Tools!
  5. Discussions

Merge the Tools!

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2659 Discussions

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  • guchhaitpralay7
     + 0 comments
    def merge_the_tools(string: str, k: int):
    length: int = len(string)

    for i in range(0, length, k):
        result: list[str] = []
        for char in string[i : i + k]:
            if char not in result:
                result.append(char)

            print("".join(result))


if __name__ == "__main__":
    string, k = input(), int(input())
    merge_the_tools(string, k)

  • ercapatti
     + 0 comments

    My code:

    def merge_the_tools(string, k): subs = [] word = ''

    for i in range(1,len(string) + 1):
    if string[i-1] not in word:
        word += string[i-1]
    if i % k == 0:
        subs.append(word)
        word = ''

for j in range(0, len(subs)):
    print(subs[j])

  • karmakar_2007
     + 0 comments
    def merge_the_tools(string, k):
    # your code goes here
    for i in range(0, len(string), k):
        print("".join(dict.fromkeys(list(string[i: i + k]))))
    
if __name__ == '__main__':
    string, k = input(), int(input())
    merge_the_tools(string, k)

  • williamgwede002
     + 0 comments

    def merge_the_tools(string, k): # your code goes here stlist = [] c = 1

    for char in string:
    if char not in stlist:
        stlist.append(char)
    if c == k:
        output = "".join(stlist)
        print(output)
        stlist.clear()
        c = 1
        continue
    c +=1

    if name == 'main': string, k = input(), int(input()) merge_the_tools(string, k)

  • zettix1
     + 0 comments

    Vanilla.

    def merge_the_tools(string, k):
    for i in range(0, len(string), k):
        seen = set()
        out = ''
        for c in string[i: i + k]:
            if c in seen:
                continue
            seen.add(c)
            out += c
        print(out)