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  1. Prepare
  2. Python
  3. Strings
  4. Merge the Tools!
  5. Discussions

Merge the Tools!

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2598 Discussions

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  • gabrielmatioli
     + 0 comments

    m = '\n'.join( ''.join(dict.fromkeys(group)) for group in [group for group in batched(string, k)])

    return m

  • akshayko1012
     + 0 comments

    import textwrap

    def merge_the_tools(string, k):

    list1=textwrap.wrap(string, k)

for value in list1:
    str1=""
    for i in value:
        if i in str1:
            pass
        else:
            str1+=i
    print(str1)

  • oletirams
     + 0 comments

    import textwrap def merge_the_tools(string, k): wrapper = textwrap.TextWrapper(width=k) h = wrapper.wrap(string) for s in h: s = list(s) for i in s: while s.count(i) > 1: s.reverse() s.remove(i) s.reverse() print(''.join(s))

  • cromwellkwasi
     + 0 comments
    def merge_the_tools(string, k):
    # your code goes here
    import textwrap
    if len(string)%k == 0:
        listed = textwrap.wrap(string,k)
    for i in range(len(listed)):
        print("".join(set(listed[i])))

  • vishalsharma6591
     + 0 comments

    This part of code should be used in the funtion given

    for i in range(0, len(string), k):
    lis=[]
    for m in range(i, i+k):
        if string[m] not in lis:
            lis.append(string[m])
    print("".join(lis))