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  1. Prepare
  2. Python
  3. Strings
  4. Merge the Tools!
  5. Discussions

Merge the Tools!

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2662 Discussions

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  • elinxsilver
     + 0 comments

    This is the best and simplest solution:

    def merge_the_tools(string, k): for i in range(len(string)): if i % k == 0: stry="" for j in range(k): if string[j+i] not in stry: stry = stry + string[j+i] print(stry)

    if name == 'main': string, k = input(), int(input()) merge_the_tools(string, k)

  • xs2ranjeet
     + 0 comments
    def merge_the_tools(string, k):
    # your code goes here
    for i in range(0, len(string), k):
        substring = string[i: i + k]
        seen = set()
        result = ""
        for ch in substring:
            if ch  not in seen:
                seen.add(ch)
                result += ch
        print(result)

  • erzwo
     + 0 comments
    def merge_the_tools(s: str, k: int):
    # iterate over substrings
    for i in range(0, len(s), k):
        # temp string
        result = ""
        # iterate over chars in substring
        for j in s[i:i + k]:
            if not j in result:
                # add char if not present
                result = result + j
        print(result)

  • guchhaitpralay7
     + 0 comments
    def merge_the_tools(string: str, k: int):
    length: int = len(string)

    for i in range(0, length, k):
        result: list[str] = []
        for char in string[i : i + k]:
            if char not in result:
                result.append(char)

            print("".join(result))


if __name__ == "__main__":
    string, k = input(), int(input())
    merge_the_tools(string, k)

  • ercapatti
     + 0 comments

    My code:

    def merge_the_tools(string, k): subs = [] word = ''

    for i in range(1,len(string) + 1):
    if string[i-1] not in word:
        word += string[i-1]
    if i % k == 0:
        subs.append(word)
        word = ''

for j in range(0, len(subs)):
    print(subs[j])