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  1. Practice
  2. Algorithms
  3. Greedy
  4. Minimum Absolute Difference in an Array
  5. Discussions

Minimum Absolute Difference in an Array

  • harshkirat2 + 1 comment

    with your approach i am able to pass only 2 test cases, but with my code i am unable to pass only 4th test case,Suggest some changes or another approach. Here is my code in C:

    #include<stdio.h>
#include<stdlib.h>
main()
{
    long int i,j,n;
    scanf("%ld",&n);
    long long int min,a[n];
    scanf("%lld%lld",&a[0],&a[1]);
    min=abs(a[0]-a[1]);
    for(i=2;i<n;i++)
    {
        scanf("%lld",&a[i]);
        for(j=0;j<i;j++)
        {
            if(abs(a[j]-a[i])<min)
                min=abs(a[j]-a[i]);
            if(min==0)
            {
                break;
            }
        }
        if(min==0)
            break;
    }
    printf("%lld",min);
}
    • ksanner + 0 comments

      Your approach is likely taking too long, since you're running O(n^2)

      If you're using just the C stdlib, try using qsort on the data set and then comparing just the neighbors for each element.