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we dont think about last index. the way become fast to find last position for element.
for(int i=0;ii) { min=min<(j-i)?min:(j-i); } }
Minimum Distances
You are viewing a single comment's thread. Return to all comments →
we dont think about last index. the way become fast to find last position for element.
for(int i=0;ii) { min=min<(j-i)?min:(j-i); } }