stdin.ReadLine()
let A = stdin.ReadLine().Split()|> Array.countBy id
stdin.ReadLine()

stdin.ReadLine().Split()|> Array.countBy id
|> Array.except A
|> Array.map fst
|> Array.sort
|> String.concat " "
|> printfn "%s"

open System

let getCount key s =
    match Seq.tryFind (fun (k, _) -> k = key) s with
    | Some(_, values) -> Seq.length values
    | None -> 0

let _ = Console.ReadLine()
let left = Console.ReadLine() |> (fun s -> s.Split(" "))
let _ = Console.ReadLine()
let right = Console.ReadLine() |> (fun s -> s.Split(" "))

let groupLeft = left |> Seq.groupBy id
let groupRight = right |> Seq.groupBy id

Seq.append left right
|> Seq.distinct
|> Seq.filter (fun key ->
    (getCount key groupLeft) <> getCount key groupRight)
|> List.ofSeq
|> Seq.sort
|> String.concat " "
|> Console.WriteLine

import Data.List (intercalate)
import Data.Array (accumArray, elems)

counts l u xs = accumArray (+) 0 (l, u) [(x, 1) | x <- xs]

missing l u xs ys =
  let cx = elems $ counts l u xs
      cy = elems $ counts l u ys
    in [i | (i, a, b) <- zip3 [l..] cx cy, a < b]

main = do
  getLine
  lx <- getLine
  getLine
  ly <- getLine
  let xs = map read $ words lx :: [Int]
      ys = map read $ words ly :: [Int]
      l = min (minimum xs) (minimum ys)
      u = max (maximum xs) (maximum ys)
  putStrLn $ intercalate " " $ map show $ missing l u xs ys

object Solution {
    import scala.io.StdIn.{readInt, readLine}

    def main(args: Array[String]): Unit = {
        val A = readList
        val B = readList
        println(missingVals(A, B).sorted.mkString(" "))
    }

    def readList: List[Int] = {
        val _ = readInt
        readLine.split(' ').map(_.toInt).toList
    }

    def missingVals[T](A: List[T], B: List[T]): List[T] = {
        val (mapA, mapB) = (countMap(A), countMap(B))
        (mapA.keySet | mapB.keySet)
            .filterNot(n => mapA(n) == mapB(n))
            .toList
    }

    def countMap[T](l: List[T]): Map[T, Int] = {
        val m = Map.empty[T, Int].withDefaultValue(0)
        l.foldLeft(m)((m, e) => m + (e -> (m(e) + 1)))
    }
}