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from collections import Counter n,arr=int(input()),list(map(int,input().split())) m,brr=int(input()),list(map(int,input().split())) a,b=Counter(arr),Counter(brr) print(*(sorted((b-a).keys())))
Let us take an example : n=10 arr=11 4 11 7 13 4 12 11 10 14 m=15 brr=11 4 11 7 3 7 10 13 4 8 12 11 10 14 12 a=Counter(arr)=Counter({11: 3, 4: 2, 7: 1, 13: 1, 12: 1, 10: 1, 14: 1}) b=Counter(brr)=Counter({11: 3, 4: 2, 7: 2, 10: 2, 12: 2, 3: 1, 13: 1, 8: 1, 14: 1}) b-a=Counter({7: 1, 3: 1, 10: 1, 8: 1, 12: 1}) (b-a).keys()=dict_keys([7, 3, 10, 8, 12]) sorted((b-a).keys())=3 7 8 10 12
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Missing Numbers
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Simple in Python 3 :-)
Explanation: