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Company Logo

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1296 Discussions

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  • 191FA07033
     + 0 comments
    s = input()
c=Counter(s).items()
s=sorted(list(c), key=lambda item: (-item[1], item[0]))[:3]
[print(_[0],_[1]) for _ in s]

  • prajwalvinod04
     + 0 comments

    To the admin,

    No matter what I try, after all test cases are successful, the problem does not appear as solved on my profile and always has the try again button. Please check.

    Regards

    Prajwal

  • arjuna23nag
     + 0 comments

    if name == 'main': s = input().strip() c = Counter(s) # Sort by (-frequency, alphabetical) top_3 = sorted(c.items(), key=lambda x: (-x[1], x[0]))[:3] for char, freq in top_3: print(char, freq)

  • maxence_qnt
     + 0 comments

    First time using lambda expression to sort a dictionnary.

    Find my code below.

    The logic is to use collections.Counter to count every letter of the company name. Then sort them firstly by the occurence, then alphabetically.

    At the beginning, I've started by using the most_common() function of Counter, but it was quite difficult to implement it in a lambda expression for me. But As I said, it was my first time with lambda expression. So if you have some advices, I am open.

    Here my code :

    from collections import Counter

if __name__ == '__main__':
    s = input()
    logo_name = Counter(s)
    #print(logo_name.keys())

    
    # Sort in the case where few letters have the same number of occurences
    key = lambda item: (-item[1], item[0])
    most_common_letters = sorted(logo_name.items(), key=key)
    #print(most_common_letters)
    
    # 3 most common letters
    most_common_letters = most_common_letters[:3]
    #print(most_common_letters)
    
    for element in most_common_letters:
        item, value = element
        print(f"{item} {value}")

  • harshal_21315911
     + 0 comments
    import math
import os
import random
import re
import sys

def occ_desc(string):
    dist = {}
    for i in string:
        dist[i] = dist.get(i, 0) + 1

    # Sort by frequency (descending), then by character (ascending)
    sorted_items = sorted(dist.items(), key=lambda item: (-item[1], item[0]))

    # Print top 3
    for key, value in sorted_items[:3]:
        print(f"{key} {value}")

if __name__ == '__main__':
    s = input()
    occ_desc(s)