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  1. Prepare
  2. Python
  3. Basic Data Types
  4. Nested Lists
  5. Discussions

Nested Lists

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4739 Discussions

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  • iyyappanij144
     + 0 comments

    stored =[] s=set() for _ in range(int(input())): name = input() score = float(input()) stored.append([name,score]) s.add(score)

    low=sorted(s)[1]
low_name=[]


low_score =[ (name, score )for name, score in stored if score== low]




for value in sorted(low_score):
    print(value[0])

  • glenn_glazer
     + 0 comments

    The code check compares order ([a,b] != [b,a]) but this constraint is not mentioned in the problem description.

  • muhaiminul00
     + 0 comments
    if __name__ == '__main__':
    
    name_list = []
    numbers = []
    for _ in range(int(input())):
        name = input()
        score = float(input())
        numbers.append(score)
        name_list.append([name, score])
    sort_by_numbers  = sorted(name_list, key=lambda name_list: name_list[1])
    
    #Input can have multiple lowest score... Creating new list to remove all lowest scores 
    low_list = [x for x in sort_by_numbers if x[1] > min(numbers)]

    final_name = [x[0] for x in low_list if x[1] == low_list[0][1] ]
    for x in sorted(final_name): print(x)

  • aspiringdataeng
     + 0 comments

    if name == 'main': n=int(input()) l=[] for _ in range(n): name = input() score = float(input()) l.append([name,score])

    grade_list=[]
for student in l:
    grade=student[1]
    if grade not in grade_list:
        grade_list.append(grade)
grade_list.sort()
second_lowest=grade_list[1]
for student in sorted(l):
    if student[1]==second_lowest:
        print(student[0])

  • kupendrav99
     + 0 comments
    if __name__ == '__main__':
    a = []         # list to store [name, score]
    s = set()      # set to store unique scores

    for _ in range(int(input())):
        name = input()
        score = float(input())
        a.append([name, score])
        s.add(score)

    slc = sorted(s)[1]  # second lowest score
    sln = []            # names with second lowest score

    for name, score in a:
        if score == slc:
            sln.append(name)

    for name in sorted(sln):
        print(name)