We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Basic Data Types
  4. Nested Lists
  5. Discussions

Nested Lists

Sort by

recency

|

4729 Discussions

|

  • aranyakdutta2029
     + 0 comments

    my solution:

    if name == 'main': mylist = [] for _ in range(int(input())): name = input() score = float(input()) mylist.append([name,score]) mylist1 = [score1[1] for score1 in mylist] mylist1.sort() myset = set(mylist1) mylist3 = list(myset) mylist2 = [] for name,score in mylist: if score == mylist3[1]: mylist2.append(name) mylist2.sort() for name in mylist2: print(name)

  • tgraphyco
     + 0 comments

    Absolutely agree — the new interface feels clunky and less intuitive. The extra steps and obstructed view make it frustrating, especially when quick data access matters. As someone in corporate headshot dubai work, I rely on clear, efficient apps to plan outdoor shoots. The older UI let me check location-specific weather instantly, which helped a lot in scheduling.

  • highlightfsy
     + 0 comments

    if name == 'main': records = {} for _ in range(int(input())): name = input() score = float(input()) records[name] = score second_lowest_score = sorted(set(records.values()))[1] second_lowest_names = sorted(name for name, score in records.items() if score == second_lowest_score) for name in second_lowest_names: print(name)

  • S4sudakra
     + 0 comments
    if __name__ == '__main__':
    records={}
    for _ in range(int(input())):
        name = input()
        score = float(input())
        records[name]=score
    for i in sorted([key for key,value in records.items() if value== sorted(set(records.values()))[1]]):
        print(i)

  • krithisri19
     + 0 comments
    if __name__ == '__main__':
    
    N = int(input())
    records = []
    scores = []
    
    if 2 <= N <= 5:
        for _ in range(N):
            name = input()
            score = float(input())
            records.append([name, score]) 
            scores.append(score) 
    else:
        print("Invalid!")
     
    #remove duplicates, sort them and get the second lowest value
    second_lowest_score = sorted(set(scores))[1]  
    
    #extract names of students who have the second lowest score
    second_lowest_name = [name for name, score in records if score ==               
                          second_lowest_score]
                          
    second_lowest_name.sort()
    print(*second_lowest_name, sep="\n") #unpacking