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  2. Python
  3. Sets
  4. No Idea!
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No Idea!

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1530 Discussions

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  • marco_perozzo
     + 0 comments

    Python 3

    n,m = tuple(map(int, input().split(" ")))
n_arr = list(map(int, input().split(" ")))
m_a_arr = set(map(int, input().split(" ")))
m_b_arr = set(map(int, input().split(" ")))

happyness = 0
for i in n_arr:
    happyness+= (i in m_a_arr) - (i in m_b_arr)

print(happyness)

  • Kuladeeppappu
     + 1 comment

    I am not sure why it is in medium level.. I realised it after I got 50 points: I solved it very easily(unsure if i did it correctly as I am new)

    Here is my solution:

    arr=list(map(int, input().split()))
arr=arr[:n]
a=set(map(int, input().split()))
b=set(map(int, input().split()))
h=0
for i in arr:
    if(i in a):
        h+=1
    elif(i in b):
        h-=1
print(h)

    `

  • manikulamkarthik
     + 0 comments

    Enter your code here. Read input from STDIN. Print output to STDOUT

    n, m = map(int, input().split())

    arr = list(map(int, input().split())) a = set(map(int, input().split())) b = set(map(int, input().split())) hap=0 for i in arr : if i in a and i in b: pass elif i not in a and i not in b: pass elif( i in a and i not in b ): hap+=1 else: hap-=1 print (hap)

  • pdaxzuniga1
     + 0 comments

    For future reference: Do not cast the full main list of objects as a set. Using a list is necessary to maintain the integrity of the count, including duplicates.

    n, l = input(), list(map(int, input().split()))
a, b = set(map(int, input().split())), set(map(int, input().split()))
print(len([x for x in l if x in a]) - len([x for x in l if x in b]))

  • pinkyrathod13
     + 0 comments
    if __name__ == "__main__":
    n = int(input())
    print(len({input().strip() for i in range(n)}))