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  2. Python
  3. Sets
  4. No Idea!
  5. Discussions

No Idea!

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1516 Discussions

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  • vv779542
     + 0 comments

    Enter your code here. Read input from STDIN. Print output to STDOUT

    n,m = map(int,input().split()) array = list(map(int,input().split())) A = set(map(int,input().split())) B = set(map(int,input().split())) happiness = 0 for i in array: if i in A: happiness += 1 if i in B: happiness -= 1 else: happiness = happiness print(happiness)

  • pranaynikhare7
     + 0 comments
    n = list(map(int,input().split()))
A = set(map(int,input().split()))
B = set(map(int,input().split()))

like = 0
for i in n:
    if i in A:
        like += 1
    elif i in B:
        like -=1

print(like)

  • ValitovVlad
     + 1 comment

    Hi there! Solution with sets

    # Enter your code here. Read input from STDIN. Print output to STDOUT
n, m = map(int, input().split()) 
arrn = list(map(int, input().split()))

# 2 disjoint sets
At = set(map(int, input().split()))
Bt = set(map(int, input().split()))
happy = 0
for i in arrn:
    if i in At:
        happy +=1 
    if i in Bt:
        happy -= 1
    else:
        happy = happy
print(happy)

  • prashantbehera19
     + 1 comment

    That's it! I am done with this stupid website. It is full of confusing and ambiguous descriptions! I am consuming more time to unserstand the problem than to actually solve it. The description of the problem should be clear and concise. I would not recommend anyone who was has come here to practice coding here. This website will make you feel down like I was feeling down since 2 days.

  • glenn_glazer
     + 0 comments

    I got this wrong initially because this note is ambiguous:

    Note: Since and are sets, they have no repeated elements. However, the array might contain duplicate elements.

    which I read as instructing me to not count duplicate elements so I made a set from the array which gives the wrong answer.