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  1. Prepare
  2. Python
  3. Numpy
  4. Array Mathematics
  5. Discussions

Array Mathematics

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328 Discussions

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  • lsloan
     + 1 comment

    My compact solution…

    import sys
import numpy as np

_ = input()  # We don't need N or M.  Skip them!
a, b = np.split(np.loadtxt(sys.stdin, int), 2)

print(a + b, a - b, a * b, a // b, a % b, a**b, sep='\n')

  • nityanarayan44
     + 0 comments
    # Dimension
inp = input()
n, m = map(int, inp.split(' '))
# print(n,m)

# Arr
A = input()
B = input()
a= numpy.array([ list(int(num) for num in A.split(' ')) ])
b= numpy.array([ list(int(num) for num in B.split(' ')) ])
# print(a, b)

# Operation
print(numpy.add(a,b))
print(numpy.subtract(a,b))
print(numpy.multiply(a,b))
print(numpy.floor_divide(a,b))
print(numpy.mod(a,b))
print(numpy.power(a,b))

  • yashdeora98294
     + 0 comments

    Here is HackerRank Array mathematics in Python solution - https://programmingoneonone.com/hackerrank-array-mathematics-problem-solution-in-python.html

  • pawardipikar
     + 1 comment

    ip = input().split(' ') N,M = int(ip[0]),int(ip[1])

    A = list(map(int,input().split(' '))) B = list(map(int,input().split(' ')))

    a = numpy.array(A, int) b = numpy.array(B, int)

    print(numpy.add(a, b)) print(numpy.subtract(a,b)) print(numpy.multiply(a,b)) print(numpy.floor_divide(a,b)) print(numpy.mod(a,b)) print(numpy.power(a,b))

  • arohi_agrawal111
     + 0 comments
    import numpy as np

n, m = map(int, input().split())

a = np.array([list(map(int, input().split())) for i in range(n)])
b = np.array([list(map(int, input().split())) for i in range(n)])

print(np.add(a, b))
print(np.subtract(a, b))
print(np.multiply(a, b))
print(np.floor_divide(a, b))
print(np.mod(a, b))
print(np.power(a, b))