Array Mathematics

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  • + 0 comments

    Here is HackerRank Array mathematics in Python solution - https://programmingoneonone.com/hackerrank-array-mathematics-problem-solution-in-python.html

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    ip = input().split(' ') N,M = int(ip[0]),int(ip[1])

    A = list(map(int,input().split(' '))) B = list(map(int,input().split(' ')))

    a = numpy.array(A, int) b = numpy.array(B, int)

    print(numpy.add(a, b)) print(numpy.subtract(a,b)) print(numpy.multiply(a,b)) print(numpy.floor_divide(a,b)) print(numpy.mod(a,b)) print(numpy.power(a,b))

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    import numpy as np
    
    n, m = map(int, input().split())
    
    a = np.array([list(map(int, input().split())) for i in range(n)])
    b = np.array([list(map(int, input().split())) for i in range(n)])
    
    print(np.add(a, b))
    print(np.subtract(a, b))
    print(np.multiply(a, b))
    print(np.floor_divide(a, b))
    print(np.mod(a, b))
    print(np.power(a, b))
    
  • + 0 comments

    import numpy as np

    n,m = map(int,input().split(' '))

    a = np.array([list(map(int,input().split(' '))) for _ in range(n)])

    b = np.array([list(map(int,input().split(' '))) for _ in range(n)])

    print(np.add(a,b)) print(np.subtract(a,b)) print(np.multiply(a,b)) print(np.floor_divide(a,b)) print(np.mod(a,b)) print(np.power(a,b))

  • + 0 comments
    import numpy as np
    
    n, m = map(int, input().split())
    
    a = np.array([list(map(int, input().split())) for _ in range(n)])
    b = np.array([list(map(int, input().split())) for _ in range(n)])
    
    operations = [
        'add',
        'subtract',
        'multiply',
        'floor_divide',
        'mod',
        'power'
    ]
    
    for op in operations:
        func = getattr(np, op)
        print(f"{func(a, b)}")