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  3. Numpy
  4. Array Mathematics
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Array Mathematics

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335 Discussions

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  • steveraden
     + 0 comments

    This doesn't pass as it doesn't produce the nested arrays of the output, but I wanted to lookup how to create a NumPy array without create an intermediate list in memory. This way below is special to the case where the input is array-like, there is a more general numpy.fromiter as well.

    import numpy as np

    n, m = map(int, input().strip().split())

    a = np.fromstring(input().strip(), sep=' ', dtype=int, count=m)

    b = np.fromstring(input().strip(), sep=' ', dtype=int, count=m)

    print(a+b)

    print(a-b)

    print(a*b)

    print(a//b) print(a%b) print(a**b)

  • lienquanaovacc1
     + 0 comments

    import numpy as np N, M = map(int, input().split()) A = np.array([list(map(int, input().split())) for _ in range(N)]) B = np.array([list(map(int, input().split())) for _ in range(N)]) print(A+B) print(A-B) print(A*B) print(A//B) print(A%B) print(A**B)

  • asterial1116
     + 0 comments
    import numpy as np 
N,M = map(int, input().split())
a = np.array([input().split() for _ in range(N)], int)
b = np.array([input().split() for _ in range(N)], int)

print(np.add(a,b))
print(np.subtract(a,b))
print(np.multiply(a,b))
print(np.floor_divide(a,b))
print(np.mod(a,b))
print(np.power(a,b).astype(int))

  • SVVBathini_w
     + 0 comments

    For Python3 Platform

    import numpy

n, m = map(int, input().split())
A = numpy.array([input().split() for _ in range(n)], int)
B = numpy.array([input().split() for _ in range(n)], int)

print(A + B)
print(A - B)
print(A * B)
print(A//B)
print(numpy.mod(A, B))
print(numpy.power(A, B))

  • sbk_63
     + 0 comments

    import numpy as np

    n = int(input().split()[0])

    a, b = [np.array([input().split() for _ in range(n)], int) for _ in range(2)]

    print(np.add(a, b), np.subtract(a, b), np.multiply(a, b), np.floor_divide(a, b), np.mod(a, b), np.power(a, b), sep='\n')