Took the input as a tuple for the dimensions of the array

nums = tuple(map(int, input().split()))
print (numpy.zeros(nums, dtype = numpy.int))
print (numpy.ones(nums, dtype = numpy.int))

These numpy challenges are not worth 20 marks. Most of them just test knowledge of a function, no thinking required.

Newbie Code

import numpy
d = tuple(  map(int,(input().split())     ))

arr1 = numpy.zeros((d), dtype = numpy.int)
print(arr1)
    
arr2 = numpy.ones((d), dtype = numpy.int)
print(arr2)

At first I used :

r,c,d = map(int, input().split(' '))

for the variables of my dimensions, but then I realized that it is possible to be given only 2 dimentions. Which would then cause an error. So instead of assigning 3 separate variables I took the whole input line and created a tuple d and used pass this tuple as the dimentions when creating the ones and zeros.

My solution:

import numpy
N = tuple(map(int,input().strip().split()))
z = numpy.zeros(N, dtype=numpy.int)
o = numpy.ones(N, dtype=numpy.int)
print (z)
print (o)

The number of inputs indicates the size of Matrix's dimension.

Such as, input three numbers:

3 3 3

it means the Matrix is 3x3x3, so call numpy.zeros((3,3,3),dtype=numpy.int) to generate the Matrix.

Nice and simple:

import numpy as np
shape = tuple(map(int, input().split()))
print(np.zeros(shape, int), np.ones(shape, int), sep='\n')