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  1. Prepare
  2. SQL
  3. Advanced Select
  4. Occupations
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Occupations

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2138 Discussions

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  • pankajarora19
     + 0 comments

    My Solution:

    with t1 as ( select distinct name, 
        row_number() over (order by name) id
            from occupations
            where lower(occupation) = 'doctor'
            ),
t2 as  ( select distinct name, 
        row_number() over (order by name) id
            from occupations
            where lower(occupation) = 'professor'
            ),  
t3 as  ( select distinct name, 
        row_number() over (order by name) id
            from occupations
            where lower(occupation) = 'singer'
            ),  
t4 as  ( select distinct name, 
        row_number() over (order by name) id
            from occupations
            where lower(occupation) = 'actor'
            )
select distinct t1.name, t2.name, t3.name, t4.name
from t1
full outer join t2
on t1.id = t2.id
full outer join t3
on t2.id = t3.id
full outer join t4
on t3.id = t4.id
order by 1, 2, 3, 4;

  • haithamdar
     + 0 comments
    SELECT [Doctor], [Professor], [Singer], [Actor]



  FROM 



  (SELECT [name]
      ,[occupation]
	  ,ROW_NUMBER() over (PARTITION by [occupation] order by [name] ) as rn
  FROM [OCCUPATIONS] ) OC

  PIVOT (
  
  max([name])
for [occupation] in ([Doctor], [Professor], [Singer], [Actor])

    ) as PO

  • ricofebrian_work
     + 0 comments

    My solutions (MySQL). hope it helps!

    First approach: using CTE

    WITH occupation_rank AS (
        SELECT
                name,
                occupation,
                ROW_NUMBER() OVER(PARTITION BY occupation ORDER BY name ASC) as rn
        FROM occupations
)
SELECT
        MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS doctor_names,
        MAX(CASE WHEN occupation = 'Professor' THEN name END) AS professor_names,
        MAX(CASE WHEN occupation = 'Singer' THEN name END) AS singer_names,
        MAX(CASE WHEN occupation = 'Actor' THEN name END) AS actor_names 
FROM occupation_rank
GROUP BY rn
ORDER BY rn;

    Second approach: using subquery

    SELECT
        MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS doctor_names,
        MAX(CASE WHEN occupation = 'Professor' THEN name END) AS professor_names,
        MAX(CASE WHEN occupation = 'Singer' THEN name END) AS singer_names,
        MAX(CASE WHEN occupation = 'Actor' THEN name END) AS actor_names
FROM (
        SELECT
                name,
                occupation,
                ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) as rn
        FROM OCCUPATIONS
) AS sorted
GROUP BY rn;

  • pralay_g
     + 0 comments
    SELECT 
    [Doctor],
    [Professor],
    [Singer],
    [Actor]
FROM (
    SELECT 
        [Name],
        [Occupation],
        ROW_NUMBER() OVER(
            PARTITION BY [Occupation] ORDER BY [Name]
        ) AS rowNumber
    FROM OCCUPATIONS
) AS SourceTable
PIVOT (
    MAX([NAME])
    FOR [Occupation] IN (
        Doctor,
        Professor,
        Singer,
        Actor
    )
) AS PivotTable;

  • mriz01
     + 1 comment

    MySQL: with ranked as (select name, occupation, row_number() over (partition by occupation order by name) as rn from occupations )

    select max(case when occupation = 'Doctor' then name end) as Doctor, max(case when occupation = 'Professor' then name end) as Professor, max(case when occupation = 'Singer' then name end) as Singer, max(case when occupation = 'Actor' then name end) as actor From Ranked Group by rn Order by rn