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  1. Simple Text Editor
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Simple Text Editor

  • sickofl
     + 0 comments

    my solotion is almost identical, passes all cases:

    s=''

    history=[]

    for i in range(int(input())):

    inpt=input().split(' ')

if inpt[0]=='1':
    history.append(s)
    s+=inpt[1]

if inpt[0]=='2':
    history.append(s)
    s=s[:-int(inpt[1])]

if inpt[0]=='3':
    print(s[int(inpt[1])-1])
if inpt[0]=='4':
    s=history.pop()