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The algorithm leverages dynamic programming and modular arithmetic to efficiently calculate the number of ways to build a LEGO wall of height ( n ) and width ( m ). Let's break down the mechanism behind this algorithm step-by-step.
Problem Breakdown
Single Row Configurations (f Array):
The f array represents the number of ways to fill a row of various widths using LEGO blocks of widths 1, 2, 3, and 4.
Initial configurations for widths 0 to 4 are known:
f[0] = 0 (no way to build a width 0 row)
f[1] = 1 (one way to build a width 1 row: [1])
f[2] = 2 (two ways to build a width 2 row: [1,1] or [2])
f[3] = 4 (four ways to build a width 3 row: [1,1,1], [1,2], [2,1], [3])
f[4] = 8 (eight ways to build a width 4 row: [1,1,1,1], [1,1,2], [1,2,1], [2,1,1], [2,2], [1,3], [3,1], [4])
Extending f for Larger Widths:
For widths greater than 4, the number of ways to build the row can be derived from the previous four widths:
f[k] = f[k-1] + f[k-2] + f[k-3] + f[k-4]
This recurrence relation holds because a row of width k can end with a block of width 1, 2, 3, or 4, leaving a subproblem of width k-1, k-2, k-3, or k-4, respectively.
Building Multi-Row Walls (pn Array):
pn[k] represents the number of ways to build a wall of width k and height n without any constraints on solidness (i.e., it might have vertical gaps).
This is computed using pn[k] = (f[k]^n) % MOD because each row is independent, and the number of ways to stack n rows is simply f[k] raised to the power of n, taken modulo ( 10^9 + 7 ).
Solid Walls (gn Array):
The gn array represents the number of ways to build a solid wall (without vertical gaps) of width k and height n.
To compute gn[k], we start by considering pn[k], which includes both solid and non-solid walls.
We then subtract the non-solid configurations:
For each possible partition of the width k into two parts, we compute the number of ways to build a solid wall of the first part and any wall (solid or non-solid) of the remaining part.
gn[k] = pn[k] - sum(gn[i] * pn[k-i] for i in range(1, k)) % MOD
This effectively subtracts all configurations where the wall is not solid, ensuring gn[k] only counts solid walls.
Why the Algorithm Works
Dynamic Programming:
The use of the f, pn, and gn arrays allows the algorithm to build up solutions to larger problems from solutions to smaller subproblems.
This avoids redundant calculations and ensures that each required value is computed only once, making the algorithm efficient.
Modular Arithmetic:
By taking all operations modulo ( 10^9 + 7 ), the algorithm keeps numbers manageable and avoids overflow.
This is essential for handling the large numbers that result from exponentiation and large sums.
Separation of Concerns:
The algorithm separates the problem into manageable parts: computing row configurations, building multi-row configurations, and ensuring solidity.
This clear separation makes the logic easier to follow and verify.
Conclusion
The algorithm leverages dynamic programming and modular arithmetic to efficiently compute the number of ways to build a solid LEGO wall of given dimensions. By breaking down the problem into smaller parts and building up solutions, it ensures both correctness and efficiency.
Lego Blocks
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The algorithm leverages dynamic programming and modular arithmetic to efficiently calculate the number of ways to build a LEGO wall of height ( n ) and width ( m ). Let's break down the mechanism behind this algorithm step-by-step.
Problem Breakdown
Single Row Configurations (
f
Array):f
array represents the number of ways to fill a row of various widths using LEGO blocks of widths 1, 2, 3, and 4.f[0] = 0
(no way to build a width 0 row)f[1] = 1
(one way to build a width 1 row: [1])f[2] = 2
(two ways to build a width 2 row: [1,1] or [2])f[3] = 4
(four ways to build a width 3 row: [1,1,1], [1,2], [2,1], [3])f[4] = 8
(eight ways to build a width 4 row: [1,1,1,1], [1,1,2], [1,2,1], [2,1,1], [2,2], [1,3], [3,1], [4])Extending
f
for Larger Widths:f[k] = f[k-1] + f[k-2] + f[k-3] + f[k-4]
k
can end with a block of width 1, 2, 3, or 4, leaving a subproblem of widthk-1
,k-2
,k-3
, ork-4
, respectively.Building Multi-Row Walls (
pn
Array):pn[k]
represents the number of ways to build a wall of widthk
and heightn
without any constraints on solidness (i.e., it might have vertical gaps).pn[k] = (f[k]^n) % MOD
because each row is independent, and the number of ways to stackn
rows is simplyf[k]
raised to the power ofn
, taken modulo ( 10^9 + 7 ).Solid Walls (
gn
Array):gn
array represents the number of ways to build a solid wall (without vertical gaps) of widthk
and heightn
.gn[k]
, we start by consideringpn[k]
, which includes both solid and non-solid walls.k
into two parts, we compute the number of ways to build a solid wall of the first part and any wall (solid or non-solid) of the remaining part.gn[k] = pn[k] - sum(gn[i] * pn[k-i] for i in range(1, k)) % MOD
gn[k]
only counts solid walls.Why the Algorithm Works
Dynamic Programming:
f
,pn
, andgn
arrays allows the algorithm to build up solutions to larger problems from solutions to smaller subproblems.Modular Arithmetic:
Separation of Concerns:
Conclusion
The algorithm leverages dynamic programming and modular arithmetic to efficiently compute the number of ways to build a solid LEGO wall of given dimensions. By breaking down the problem into smaller parts and building up solutions, it ensures both correctness and efficiency.