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  1. Merge two sorted linked lists
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Merge two sorted linked lists

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  • douglasmarsola
     + 0 comments

    Typescript seems to be available, but it is not implemented.

  • seanjennings976
     + 0 comments

    C# solution after consulting geeksforgeeks when I got stuck

    static SinglyLinkedListNode mergeLists(SinglyLinkedListNode head1, SinglyLinkedListNode head2) {
        
        if (head1 is null) return head2;
        if (head2 is null) return head1;
        
        if (head1.data <= head2.data)
        {
            head1.next = mergeLists(head1.next, head2);
            return head1;
        }
        else
        {
          head2.next = mergeLists(head1, head2.next);
          return head2; 
        }
    }

  • Kole_Soto
     + 0 comments

    C#, test case two fails. It seems there is 1 test case, for which the first linked list is 8 ints. The next set of ints for list 2 are unordered it seems. All of my other test cases pass.

  • sabir_obul
     + 0 comments

    the explanation part with sample had mistake ,

    Explanation

    The first linked list is: 1 -> 3 -> 7 ->NULL The second linked list is: 3->4->NULL Hence, the merged linked list is: 1->2->3->3->4->NULL where is the 7 gone from list 1 ?

  • robertstanton95
     + 0 comments

    Bit hacky but...

    def mergeLists(head1, head2):
    
    merged = SinglyLinkedList()
    
    while head1 is not None and head2 is not None:
        if head1.data < head2.data:
            merged.insert_node(head1.data)
            head1 = head1.next
        else:
            merged.insert_node(head2.data)
            head2 = head2.next
            
    if head1 is not None:
        while head1 is not None:
            merged.insert_node(head1.data)
            head1 = head1.next
            
    if head2 is not None:
        while head2 is not None:
            merged.insert_node(head2.data)
            head2 = head2.next
            
    return merged.head