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In the code snippet (which will not pass due to time constraints) word does not exist in T until it's loop checking against the current set of T is complete and it is added at the end. See the line after the T loop to add the current word to T.
It is not possible to have T and word refer to the same element at the same time. nless you mean there is a duplicate word (and therefore the set fails).
You could think of word as a "yet to check" list and T as a "has been checked " list
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In the code snippet (which will not pass due to time constraints) word does not exist in T until it's loop checking against the current set of T is complete and it is added at the end. See the line after the T loop to add the current word to T.
It is not possible to have T and word refer to the same element at the same time. nless you mean there is a duplicate word (and therefore the set fails).
You could think of word as a "yet to check" list and T as a "has been checked " list