We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Interview Preparation Kits
  3. 1 Week Preparation Kit
  4. Day 6
  5. Simple Text Editor

Simple Text Editor

Implement a simple text editor. The editor initially contains an empty string, . Perform operations of the following types:

  1. append - Append string to the end of .
  2. delete - Delete the last characters of .
  3. print - Print the character of .
  4. undo - Undo the last (not previously undone) operation of type or , reverting to the state it was in prior to that operation.

Example 


operation
index   S       ops[index]  explanation
-----   ------  ----------  -----------
0       abcde   1 fg        append fg
1       abcdefg 3 6         print the 6th letter - f
2       abcdefg 2 5         delete the last 5 letters
3       ab      4           undo the last operation, index 2
4       abcdefg 3 7         print the 7th characgter - g
5       abcdefg 4           undo the last operation, index 0
6       abcde   3 4         print the 4th character - d

The results should be printed as: 

f
g
d

Input Format

The first line contains an integer, , denoting the number of operations.
Each line of the subsequent lines (where ) defines an operation to be performed. Each operation starts with a single integer, (where ), denoting a type of operation as defined in the Problem Statement above. If the operation requires an argument, is followed by its space-separated argument. For example, if and , line will be 1 abcd.

Constraints

  • The sum of the lengths of all in the input .
  • The sum of over all delete operations .
  • All input characters are lowercase English letters.
  • It is guaranteed that the sequence of operations given as input is possible to perform.

Output Format

Each operation of type must print the character on a new line.

Sample Input

STDIN   Function
-----   --------
8       Q = 8
1 abc   ops[0] = '1 abc'
3 3     ops[1] = '3 3'
2 3     ...
1 xy
3 2
4 
4 
3 1

Sample Output

c
y
a

Explanation

Initially, is empty. The following sequence of operations are described below:

  1. . We append to , so .
  2. Print the character on a new line. Currently, the character is c.
  3. Delete the last characters in (), so .
  4. Append to , so .
  5. Print the character on a new line. Currently, the character is y.
  6. Undo the last update to , making empty again (i.e., ).
  7. Undo the next to last update to (the deletion of the last characters), making .
  8. Print the character on a new line. Currently, the character is a.