My very Janky Javascript solution

thoughts?

function timeConversion(s) {
    let convertedString = ''
    
        let sr = s.substring(0, 8)
        const stringArr = sr.split(":")
        const convert = Number(stringArr[0])
        if(s.charAt(s.length-2) == 'P') {
            if(convert == 12) {
                stringArr[0] = 12
            } else {
                stringArr[0] = convert + 12
            }
        } else {
            if(s.charAt(s.length-2) == 'A'){
                if(convert == 12) {
                    stringArr[0] = "00"
                } 
            }
        }
        stringArr.forEach(function(e, idx, array) {
            if(idx === array.length-1){
                convertedString += e;
                return
            }
            convertedString += e + ':';
        })
    return convertedString
}

24 hours ago+ 0 comments

but didn't know why is he failing testcase # 4 :(

j = ['01','02','03','04','05','06','07','08','09','10','11']

def timeConversion(s):
    if s[8:] == 'AM':
        time = s.replace('AM','')
        a = time.split(':')
        if a[0] == '12':
            a[0] = '00'
        else:
            pass
        print(':'.join(a))
    
    elif s[8:] == 'PM':
        time2 = s.replace('PM','')
        b = time2.split(":")
        if b[0] in j:
            b[0] = int(b[0])
            b[0] += 12
            b[0] = str(b[0])
            print(':'.join(b))
        if b[0] == '12':
            print(':'.join(b))

s = input()
timeConversion(s)

2 days ago+ 0 comments

I don't know if it's considered "cheating", but I used a real datetime parser:

import java.time.format.DateTimeFormatter;
import java.time.LocalTime;

(...)
public static String timeConversion(String s) {
        
    DateTimeFormatter sourceFormat = DateTimeFormatter.ofPattern("hh:mm:ssa");
    DateTimeFormatter targetFormat = DateTimeFormatter.ofPattern("HH:mm:ss");
        
    String formattedTime = LocalTime.parse(s, sourceFormat).format(targetFormat);
    
    return formattedTime;
    
}

3 days ago+ 0 comments

What do you think about this solution?

public static String timeConversion(String s) {
        String[] ss = s.split(":");
        String res = "";
        if(ss[0].equals("12") && ss[ss.length-1].contains("AM")) {
            res = "00:" + ss[1] + ":" + ss[ss.length-1].substring(0, 2);
        }
        else if(Integer.parseInt(ss[0]) > 0 && Integer.parseInt(ss[0]) < 12) {
            if(ss[ss.length-1].contains("AM")) {
                res = s.substring(0, s.length() - 2);
            }
            else if(ss[ss.length-1].contains("PM")) {
                res = (Integer.parseInt(ss[0]) + 12) + ":" + ss[1] + ":" + ss                           [ss.length-1].substring(0, 2);
            }
        }
        else {
            res = s.substring(0, s.length() - 2);
        }
        return res;
    }

}

5 days ago+ 0 comments

any guesses why this code is giving an error?

public static String timeConversion(String s) { String newTime = "";

String temp = "";

String no = "";

 if(s.charAt(s.length()-2)=='A' && Integer.valueOf(s.substring(0,2))==12) temp.concat("00:");

else if(s.charAt(s.length()-2)=='A') temp.concat(s.substring(0,3));

if(s.charAt(s.length()-2)=='P'){

int hel = Integer.valueOf(s.substring(0,2));

hel+=12;

if(hel==24) temp =  newTime.concat("00:");

else temp =  newTime.concat(hel+":");

}

String Final = temp.concat(s.substring(3,8)); return Final;

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