def solve(n, m): return (n*m)-1
python 3
def solve(n: int, m: int) -> int: """ >>> solve(3, 1) 2 """ return n * m - 1 if __name__ == '__main__': import doctest doctest.testmod()
def solve(n, m): # Write your code here return m*n-1
I got this immediately thanks to the same puzzle being in a Professor Layton game I played in 2010.
C++ (you have to change input from an int to a long)
long solve(long n, long m) { return (n*m)-1; }
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