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  1. Prepare
  2. Algorithms
  3. Search
  4. Pairs
  5. Discussions

Pairs

  • agoston_fung
     + 56 comments

    Nice and simple with Javascript, after sorting the numbers.

        var i=0,j=1,count=0;
    
    while(j < n) {
        var diff = nums[j] - nums[i];
        
        if (diff == k) {
            count++;
            j++;
        } else if (diff > k) {
            i++;
        } else if (diff < k) {
            j++;
        }
    }