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  1. Prepare
  2. Java
  3. Strings
  4. Pattern Syntax Checker
  5. Discussions

Pattern Syntax Checker

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401 Discussions

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  • bhujbalr562
     + 0 comments

    import java.util.Scanner; import java.util.regex.*;

    public class Solution { public static void main(String[] args){ Scanner in = new Scanner(System.in); int testCases = Integer.parseInt(in.nextLine()); while(testCases>0){ String pattern = in.nextLine();

            //Write your code

        try {
            Pattern.compile(pattern);
              System.out.println("Valid");
        } catch (PatternSyntaxException exc) {
            System.out.println("Invalid");
        }

        testCases;
    }

    in.close();
    }
}

  • dhastansitthi
     + 0 comments

    Any solutions without "try/catch" block ?

  • KimberlyRuffin63
     + 0 comments

    such a great exercise for sharpening regex skills! Laser teeth whitening Edmonton

  • komal_kumari
     + 0 comments
        Scanner in = new Scanner(System.in);
    int testCases = Integer.parseInt(in.nextLine());

    while (testCases > 0) {
        String pattern = in.nextLine();
        try {
            Pattern.compile(pattern); 
            System.out.println("Valid"); 
        } catch (PatternSyntaxException e) { 
            System.out.println("Invalid");
        }
        testCases--;
    }
    in.close();
}

  • lmrivera2366
     + 1 comment

    public static void main(String[] args) {

        Scanner in = new Scanner(System.in);
    int testCases = Integer.parseInt(in.nextLine());

    while(testCases > 0){
        String pattern = in.nextLine();
          try {
            "".split(pattern);
            System.out.println("Valid");

          } catch (Exception e){
            System.out.println("Invalid");
          }
          testCases--;
    }
    in.close();
}