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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Sequence Equation
  5. Discussions

Sequence Equation

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1545 Discussions

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  • afzal_saiyed931
     + 0 comments
    def permutationEquation(p):
    # Write your code here
    temp = {value: index + 1 for index, value in enumerate(p)}
    result = []
    for x in range(1, len(p)+1):
        i = temp.get(x)
        j = temp.get(i)
        result.append(j)
        
    return result

  • spriyamalar
     + 0 comments
    public static List<Integer> permutationEquation(List<Integer> p) {
    Map<Integer, Integer> map = IntStream.
            range(0, p.size()).
            boxed().
            collect(Collectors.toMap(s-> p.get(s), s-> s+1));
    List<Integer> result = IntStream.range(1, p.size()+1).
        boxed().
        map(map::get).
        map(map::get).
        collect(Collectors.toList());
    return result;
}

  • prajjwal077
     + 0 comments

    Here's my easiest javascript solution :)

    let result=Array.from({ length: p.length });
    let positionVal;
    
    p.forEach((elem,index)=>{
        positionVal=(p.indexOf(index+1))+1;
        result[elem-1]=positionVal
    })
  
    return result;

  • Qwerty9927
     + 0 comments

    Ts version

    function permutationEquation(p: number[], n: number): number[] {
const reverseIndex = new Map<number, number>(p.map((item, index) => [item, index + 1]))

return (new Array(n)).fill(0).map((item, index) => {
    return reverseIndex.get(reverseIndex.get(index + 1))
})
}

  • yashdeora98294
     + 0 comments

    Here is problem solution in Python, Java, C++, C and Javascript - https://programmingoneonone.com/hackerrank-sequence-equation-problem-solution.html