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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Sequence Equation
  5. Discussions

Sequence Equation

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1549 Discussions

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  • davidgomezcode
     + 0 comments

    My solution

    def permutationEquation(p): return [p.index(p.index(x) + 1) + 1 for x in sorted(p)]

    I am just learning Python, so the syntax where I use one line with the for cycle at the end is new to me. Originally I wrote:

    def permutationEquation(p): answer = []

    for x in sorted(p):
    answer.append(p.index(p.index(x) + 1) + 1)    

print(answer)

  • wifivop476
     + 0 comments

    I totally agree! When I had just read the problem, I thought that I probably could get it in one line of code. Focusing on reducing equipment failure as a mindset, I broke the entire problem into just a few steps and was able to get a solution that only took one line of code!

  • akulbachandra67
     + 0 comments

    **Mine Python Solution **

    def permutationEquation(p):
    # Write your code here
    a = [p.index(i)+1 for i in range(min(p),max(p)+1)]
    b = [p.index(i)+1 for i in a ]
return b

  • troytjh
     + 0 comments

    C++ solution

    vector<int> permutationEquation(vector<int> p)
{
    vector<int> o(p.size());
    int j,k=0;
    for (int i = 1; i <= p.size(); ++i)
    {
        while (p[j] != i && j < p.size()) {++j;};
        while (p[k] != j+1 && k < p.size()) {++k;};
        
        o.at(i-1) = k+1;
        
        j = 0;
        k = 0;
    }
    
    return o;
}

  • afzal_saiyed931
     + 0 comments
    def permutationEquation(p):
    # Write your code here
    temp = {value: index + 1 for index, value in enumerate(p)}
    result = []
    for x in range(1, len(p)+1):
        i = temp.get(x)
        j = temp.get(i)
        result.append(j)
        
    return result