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  1. Prepare
  2. Java
  3. Data Structures
  4. Java Map
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Java Map

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379 Discussions

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  • sanket_darekar46
     + 0 comments

    The below code is not running into hackerrank and same code get compiled and runined successfully.

  • sanket_darekar46
     + 0 comments

    //Complete this code or write your own from scratch import java.util.; import java.io.;

    class Solutions{ public static void main(String []argh) {

        Map <String,Integer> hashMapPhoneRecord
                           = new HashMap<>();
    Scanner in = new Scanner(System.in);
    //System.out.println("Enter nth value");
    int n=in.nextInt();
    in.nextLine();
    for(int i=0;i<n;i++)
    {
        String name=in.nextLine();
        int phone=in.nextInt();
        hashMapPhoneRecord.put(name, phone);
        in.nextLine();
    }
    while(in.hasNext())
    {
        String s=in.nextLine();
        if(hashMapPhoneRecord.containsKey(s))
           System.out.println(s + "=" + hashMapPhoneRecord.get(s));

         else
            System.out.println("Not Found");

    }
    in.close();


}

    }

  • Damian_GDO_92
     + 0 comments
    //Complete this code or write your own from scratch
import java.util.*;
import java.io.*;

class Solution{
	public static void main(String []argh)
	{
		Scanner in = new Scanner(System.in);
        
		int n = in.nextInt();
        
        if (n < 0 || n > 100000) {
            throw new IllegalArgumentException("The number of people-phones cannot be lower than 0 or greater than 100,000");
        }
		
        Map<String, Integer> phoneBook = new HashMap<>();
        
        in.nextLine();
        
		for(int i=0; i<n; i++) {
			String name = in.nextLine().toLowerCase();
			Integer phone = in.nextInt();
            in.nextLine();
			
            if (String.valueOf(phone).length() != 8) {
                throw new IllegalArgumentException(String.format("The phone number %s is not 8 digits long", phone));
            }
            
            phoneBook.put(name, phone);
		}
        
		while(in.hasNext()) {
			String s = in.nextLine().toLowerCase();
            
            Integer phone = phoneBook.get(s);
            
            if (phone == null) {
                System.out.println("Not found");
            } else {
                System.out.println(String.format("%s=%d", s, phone));
            }
		}
	}
}

  • yashdeora98294
     + 0 comments

    Here is Java Map solution - https://programmingoneonone.com/hackerrank-java-map-problem-solution.html

  • navamsharma142
     + 1 comment

    I don't understand the sample testcase. Tom clearly has a phone number why the output is not found??