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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Picking Numbers
  5. Discussions

Picking Numbers

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2606 Discussions

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  • torvanna24
     + 0 comments

    Hey folks,

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  • devloper2345
     + 0 comments
    def pickingNumbers(a):
    a.sort()
    ml = 0
    for i in range(len(a)):
        la = [a[i]]
        for j in range(i+1, len(a)):
            if abs(a[i]-a[j]) <= 1:
                la.append(a[j])
        
        print(la)
        if len(la) > ml:
            ml = len(la) 
            
    return ml

  • sankatana02
     + 0 comments

    Flag array method (write in kotlin):

    fun pickingNumbers(a: Array<Int>): Int {
    // Write your code here
    var maxLength = 1
    var maxValue = 0
    val frequencies = MutableList(100) { 0 }

    a.forEach { num ->
        maxValue = Math.max(num, maxValue)
        frequencies[num]++
    }

    for (i in 1..maxValue) {
        val subListLength = frequencies[i] + frequencies[i - 1]
        maxLength = Math.max(maxLength, subListLength)
    }

    return maxLength
}``

  • zettix1
     + 0 comments

    Simple unsorted n-squared solution.

    // Write your code here
    int maxcount = 0;
    for (int i = 0; i < a.size(); i++) {
        int v = a.get(i);
        int count = 1;
        for (int j = 0; j < a.size(); j++) {
            if (i == j) {
                continue;
            }   
            int q = a.get(j);
            if (v == q || v == q - 1) {
                count++;
            }   
        }   
        if (count > maxcount) {
            maxcount = count;
        }
    return maxcount;
}

  • henrylong7191
     + 0 comments
    function pickingNumbers(a: number[]): number {
    
    // sort arr in ascding order
    a.sort((x,y)=>x-y);
    
    let ans = 0;
    let window_start = 0;
    
    for (let window_end = 0; window_end < a.length; window_end++) {
        
        while (a[window_end] - a[window_start] > 1) {
            window_start ++;
        }
        
         const window_size = window_end - window_start +1;
         
         ans = Math.max(window_size, ans);
    }
    
    return ans;
}