Here is my c++ solution, you can watch the explanation here : https://youtu.be/OqevjJbsN2Q

void plusMinus(vector<int> arr) {
    double sp, sn, sz, pa = 1.0 / arr.size();
    sp = sn = sz = 0;
    for(int i = 0; i < arr.size(); i++){
        if(arr[i] > 0) sp+= pa;
        else if(arr[i]<0) sn+= pa;
        else sz+= pa;
    }
    cout << setprecision(6) << fixed;
    cout << sp <<endl;
    cout << sn <<endl;
    cout << sz <<endl;
}

C# : public static void plusMinus(List arr) { decimal positive =0; decimal negative = 0; decimal zero =0 ; int total= arr.Count;

for (int i = 0; i < total; i++ ){
   if (arr[i] > 0){
       positive++;}
   else if (arr[i] <0){
       negative++;}
   else {zero++;}}

Console.WriteLine(positive /total); Console.WriteLine(negative /total); Console.WriteLine(zero / total);

   else {zero++;}}

Console.WriteLine(positive /total); Console.WriteLine(negative /total); Console.WriteLine(zero / total);

l = len(s) c1 = 0 c2 = 0 c3 = 0

for i in s: if i>0: c1 += 1 if i<0: c2 += 1 elif i == 0: c3 += 1 listc = [] listc.append(c1) listc.append(c2) listc.append(c3) for i in listc: result = i/l print(f'{result}00000')

def plusMinus(arr): # Write your code here p=n=z=0

for i in range(len(arr)):
    if arr[i]<0:
        n=n+1
    elif arr[i]>0:
        p=p+1
    else:
        z=z+1
P=float(p/len(arr))
N=float(n/len(arr))
Z=float(z/len(arr))
print(round(P, 6))
print(round(N, 6))
print(round(Z, 6))

if name == 'main': n = int(input().strip())

arr = list(map(int, input().rstrip().split()))

plusMinus(arr)

GO

func plusMinus(arr []int32) {
    var positive, negative, zero float64
    var n = float64(len(arr))

for i,_:= range arr{
    //For positive
    if arr[i] > 0{
        positive ++
    }else if arr[i] < 0{
        negative++
    }else{
        zero++
    }
}
fmt.Printf("%.6f \n%.6f \n%.6f", positive/float64(n), negative/float64(n), zero/float64(n))

}