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  1. Prepare
  2. C
  3. Introduction
  4. Pointers in C
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Pointers in C

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  • kedarbista251
     + 0 comments

    This one can also be the simple one

    include

    void update(int *a,int *b) { int temp; temp = *a; *a = *a + *b; if(temp>*b) { *b = temp - *b; } else { *b = *b - temp; } // return *a; // return *b; // Complete this function
    }

    int main() { int a, b; int *pa = &a, *pb = &b;

    scanf("%d %d", &a, &b);
update(pa, pb);
printf("%d\n%d", a, b);

return 0;

    }

  • krushnajunghare1
     + 0 comments
    #include <stdio.h>

void update(int *a,int *b) {
    int max, diff;
    max = *a + *b;
    diff = abs(*a - *b);
    printf("%d\n%d",max,diff);    
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    //printf("%d\n%d", a, b);

    return 0;
}

  • ibnulmisbah
     + 0 comments

    Pointer in C.

    Here is an Easy Solution of the problem :

    #include <stdio.h>
#include <stdlib.h>

int update(int *a, int *b) {
    int temp_a = *a, temp_b = *b;

    *a = temp_a + temp_b;
    *b = abs(temp_a - temp_b);
}

int main() {

    int frst, scnd;
    int *p_frst = &frst, *p_scnd = &scnd;

    scanf("%d %d", &frst, &scnd);

    update(p_frst, p_scnd);

    printf("%d\n%d\n", frst, scnd);

    return 0;
}

  • caohongphuc912
     + 0 comments
    #include <stdio.h>
#include <math.h>
void update(int *a,int *b) 
{
      int t1=*a, t2=*b;
      *a = t1+t2;
      *b = abs(t1-t2);
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);

    return 0;
}

  • LogicArchitect_
     + 0 comments
    #include <stdio.h>
#include <stdlib.h>

void update(int *a,int *b) {
    int temp = *a;
    *a = *a + *b;
    *b = abs(temp - *b);
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);

    return 0;
}