We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
- Prepare
- Artificial Intelligence
- Probability & Statistics - Foundations
- Poisson Distribution #2
- Discussions
http://www.cimt.org.uk/projects/mepres/alevel/stats_ch6.pdf
Using the equation of variance Var[X] = E[X^2] - E[X]^2 -> equation(1)
For a Poisson distribution, Var[X] = E[X] -> equation(2)
we can rewrite equation(1) as
E[X^2] = Var[X] + E[X]^2
or E[X^2] = E[X] + E[X]^2 -> From equation(2)
On substituting these values in the cost equation we get 226.176 and 286.100
is not there something missing? what is the occurence or interval of a machine breaking?
Need a link or somekind of info to find out how to go about this? Thanks.