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    http://www.cimt.org.uk/projects/mepres/alevel/stats_ch6.pdf

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    Using the equation of variance Var[X] = E[X^2] - E[X]^2 -> equation(1)

    For a Poisson distribution, Var[X] = E[X] -> equation(2)

    we can rewrite equation(1) as

    E[X^2] = Var[X] + E[X]^2

    or E[X^2] = E[X] + E[X]^2 -> From equation(2)

    On substituting these values in the cost equation we get 226.176 and 286.100

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    is not there something missing? what is the occurence or interval of a machine breaking?

  • + 1 comment

    Need a link or somekind of info to find out how to go about this? Thanks.

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