def reversePrint(llist): # Write your code here curr = llist if curr is None: return reversePrint(curr.next) print(curr.data)

I was working on this reverse-print linked list problem, and the way I understood it was by comparing it to the Denny’s breakfast menu. You don’t change anything on the menu, you just read it from the bottom instead of the top. Same with the list: go to the end first, then print everything backward.Select 44 more words to run Humanizer.

implementation in TypeScript

function reversePrint(llist: SinglyLinkedListNode): void {
    if(llist === null ) return;
    reversePrint(llist.next!)
    console.log(llist.data)
 
}

def reversePrint(llist): # Write your code here

if llist.next:
    reversePrint(llist.next)
print(llist.data)

Golang Solution with recursive:

func reversePrint(llist *SinglyLinkedListNode) {
    if llist.next != nil {
        reversePrint(llist.next)
    }
    fmt.Println(llist.data)
}