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  1. Prepare
  2. Data Structures
  3. Linked Lists
  4. Print in Reverse
  5. Discussions

Print in Reverse

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991 Discussions

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  • tongyou1995
     + 0 comments

    Python 3 solution, not the most efficient:

    def reversePrint(llist):
    vals = []
    while llist:
        vals.append(llist.data)
        llist = llist.next
    if vals:    
        reversed_vals = reversed(vals)
    for t in reversed_vals:
        print(t)

  • nelucampean
     + 1 comment

    To the Hackerrank Team!!!! Please fix the C# variants for SingleLinkedList problems!!! Almost all of them give compiler errors. The solutions work (adapted) in java but they won't compile in C# because of the input parsing code. Thank you!

  • mdsanz
     + 0 comments

    My Java solution:

    public static void reversePrint(SinglyLinkedListNode llist) {
        SinglyLinkedListNode reverseList = null;
        SinglyLinkedListNode current = llist;
        
        while (current != null) {
            SinglyLinkedListNode temp = new SinglyLinkedListNode(current.data);
            temp.next = reverseList;
            reverseList = temp;
            current = current.next;
        }
        
        while (reverseList != null) {
            System.out.println(reverseList.data);
            reverseList = reverseList.next;
        }
    }

  • ericopokuantwi31
     + 0 comments

    JavaScript Solution:

    function reversePrint(llist) {
    // Write your code here
    if (llist == null) return;
    let current = llist;
    let stack = [];
    while (current) {
        stack.push(current);
        current = current.next
    }
    while (stack.length > 0) {
        console.log(stack.pop().data);
    }
}

  • emhhacker
     + 0 comments

    My Java solution with linear time complexity and constant space complexity using recursion:

    public static void reversePrint(SinglyLinkedListNode llist) {
        if(llist == null) return;
        
        reversePrint(llist.next);
        
        System.out.println(llist.data);
    }