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  1. Prepare
  2. Data Structures
  3. Linked Lists
  4. Print in Reverse
  5. Discussions

Print in Reverse

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994 Discussions

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  • raditzlawliet
     + 0 comments

    Golang Solution with recursive:

    func reversePrint(llist *SinglyLinkedListNode) {
    if llist.next != nil {
        reversePrint(llist.next)
    }
    fmt.Println(llist.data)
}

  • seth_adkins
     + 0 comments

    c++ solution using stack

    void reversePrint(SinglyLinkedListNode* llist) {
    std::stack<int> stack;
    SinglyLinkedListNode* node = llist;
    while (node != NULL) {
        stack.push(node->data);
        node = node->next;
    }
    while (!stack.empty()) {
        printf("%d\n", stack.top());
        stack.pop();
    }
}

  • ms_15091993
     + 0 comments

    Java Solution Using Tail Recursion

    public static void reversePrint(SinglyLinkedListNode llist) {
        SinglyLinkedListNode current = llist;

        if(current != null){
                reversePrint(current.next);
                System.out.println(current.data);
        }
}

    }

  • tongyou1995
     + 0 comments

    Python 3 solution, not the most efficient:

    def reversePrint(llist):
    vals = []
    while llist:
        vals.append(llist.data)
        llist = llist.next
    if vals:    
        reversed_vals = reversed(vals)
    for t in reversed_vals:
        print(t)

  • nelucampean
     + 1 comment

    To the Hackerrank Team!!!! Please fix the C# variants for SingleLinkedList problems!!! Almost all of them give compiler errors. The solutions work (adapted) in java but they won't compile in C# because of the input parsing code. Thank you!