You are viewing a single comment's thread. Return to all comments →
cpp
void printLinkedList(SinglyLinkedListNode* head) { auto current = head; while(current){ std::cout << current->data << std::endl; current = current->next; } }
Seems like cookies are disabled on this browser, please enable them to open this website
Print the Elements of a Linked List
You are viewing a single comment's thread. Return to all comments →
cpp