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  1. Prepare
  2. Python
  3. Sets
  4. Check Subset
  5. Discussions

Check Subset

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945 Discussions

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  • dilajevolves
     + 0 comments
    for _ in range(int(input())):
    _,A = int(input()) , set(map(int,input().split()))
    _,B = int(input()) , set(map(int,input().split()))
    print(A.issubset(B)) # Alternative : print(A&B == A)

  • neha_singh19aug
     + 0 comments
    test_cases=int(input())
sets_list=[ [int(input()),set(map(int,input().split())),int(input()),set(map(int,input().split()))] for i in range(test_cases)]
for sets in sets_list:
    print(sets[1].intersection(sets[-1])==sets[1])

  • rohitambasta_ii1
     + 0 comments
    T= int(input())
for inputs in range(T):
    no_of_elements_in_A = int(input())
    A = set(input().split())
    no_of_elements_in_B = int(input())
    B = set(input().split())
    
    if len(A.difference(B)) == 0:  # or, A.difference(B)==set()
        print("True")
    else:
        print("False")

  • guddu1129
     + 0 comments

    t=int(input())

    for _ in range(t): n=int(input()) a=set(map(int,input().split())) m=int(input()) b=set(map(int,input().split())) if a.intersection(b) == a: print(True) else: print(False)

  • msh_123
     + 0 comments

    T = int(input())

    for i in range(T):

    a = input()
set_1 = set(map(int,input().split()))
b = input()
set_2 = set(map(int,input().split()))
c = set_1.difference(set_2)
if len(c)>0:
    print(False)
else:
    print(True)