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  1. Prepare
  2. Python
  3. Collections
  4. Collections.OrderedDict()
  5. Discussions

Collections.OrderedDict()

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720 Discussions

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  • rohitambasta_ii1
     + 0 comments

    Without any module:

    N = int(input())

item_name= []
price_list =[]

for _ in range(N):
    *item, price = input().split()
    item_name.append(' '.join(item))
    price_list.append(int(price))

unique_item= []
unique_price= []

for item, price in zip(item_name, price_list):
    if item not in unique_item:
        unique_item.append(item)
        unique_price.append(price)     
    else:
        ind= unique_item.index(item)
        unique_price[ind]= unique_price[ind]+ price

for item, total_price in zip(unique_item, unique_price):
    print(item, total_price)

  • sumitgsh19
     + 0 comments

    IMO: This problem may be helpful to know what is OrderedDict? However Python version 3.10 and beyond already has dictionary as ordered .

    FYI: Used OrderDict from collection or dict() solves the problem

    Do let me know your opinion?

  • yashdeora98294
     + 0 comments

    Here is HackerRank Collections.OrderedDict() in python solution - https://programmingoneonone.com/hackerrank-collections-ordereddict-solution-in-python.html

  • fam_lee_top
     + 0 comments

    This is a bit of a wierd question, implying the computer is input lots of different lines instead of just a single input, for _ in range(int(input())): print (input())

  • Inspired95
     + 1 comment
    from collections import OrderedDict

n = int(input())
item_list = OrderedDict()
for _ in range(n):
    item = input().split()
    key = ' '.join(item[:-1])
    value = int(item[-1])
    item_list[key] = item_list.get(key,0)+value
for k,v in item_list.items():
    print(k,v)