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Python If-Else
Python If-Else
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def evod(n): if n%2!=0: print("Weird") count=1 while count<=100: if n%2==0 and n<=5: print("Not Weird") break elif n%2==0 and n>=6 and n<=20: print("Weird") break elif n%2==0 and n>=20: print("Not Weird") break else: pass evod(20) May i know why odd conditon is failed in my case
n = int(input()) if 6<=n<=20 and n % 2 == 0: print('Weird') elif n%2 == 0: print('Not Weird') else: print('Weird')
n = int(input()) if n%2 != 0: print('Wierd') elif n>1 and n<6: print('Not Wierd') elif n>5 and n<21: print('Wierd') elif n>20: print('Not Wierd') Any idea why this is wrong
n = int(input()) if n % 2 !=0: print("Weird") elif n<=5: print("Not Weird") elif n<=20: print("Weird") else: print("Not Weird")
n = int(input()) print("Weird" if n %2 != 0 or 6<=n<=20 else "Not Weird")
A one liner