We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Introduction
  4. Python If-Else
  5. Discussions

Python If-Else

Sort 2779 Discussions, By:

  • Diapolo10
     + 140 comments

    Fairly straightforward even without using if-else statements:

    n = int(input().strip())
check = {True: "Not Weird", False: "Weird"}

print(check[
        n%2==0 and (
            n in range(2,6) or 
            n > 20)
    ])

    I defined a simple dictionary. If the value it gets is true, the program prints "Not Weird", and if it's false "Weird" is printed. Then I simply created a bunch of statements that evaluate to either True or False.

    Sure, one could argue that this is against the rules because the task was all about if-else statements, but I wanted to see if an alternative solution was better.

    EDIT: Replaced the list comprehension with a simple boolean expression

  • TheCodeHere
     + 10 comments

    I am pretty proud of my code, i think this is the best option:

    n = int(raw_input())

if n%2==0 and (n in range(2,6) or n>20 ):
    print "Not",

print "Weird"

  • Jitender98
     + 25 comments

    Question specifically asks to use "If-Else",So I did.

    n = int(input())
if n % 2 == 0:
    if n in range(2,6):
        print("Not Weird")

    elif n in range(6,21):
        print("Weird")

    elif n > 20:
        print("Not Weird")
else:
    print("Weird")

  • lucasisaacbr
     + 5 comments
    if __name__ == '__main__':
    n = int(raw_input())
    if n % 2 != 0 or n > 5 and n < 21 :
        print("Weird")
    else: 
        print("Not Weird")

  • zereiji
     + 11 comments

    My solution :),

    if __name__ == '__main__':
  n = int(input())
  print(("Not " if n%2==0 and (n<=4 or n>20) else "") + "Weird")
Load more conversations