Diapolo10 Fairly straightforward even without using if-else statements:
n = int(input().strip()) check = {True: "Not Weird", False: "Weird"} print(check[ n%2==0 and ( n in range(2,6) or n > 20) ])
I defined a simple dictionary. If the value it gets is true, the program prints "Not Weird", and if it's false "Weird" is printed. Then I simply created a bunch of statements that evaluate to either True or False.
Sure, one could argue that this is against the rules because the task was all about if-else statements, but I wanted to see if an alternative solution was better.
EDIT: Replaced the list comprehension with a simple boolean expression
xulei_vip it's pretty neat！
DevlinKain Why does it say 29 fails when I run the test case? Problem is, 29 %2 != 0, so it should return weird. Why woould it return anything else after failing the first test case?
Diapolo10 I have no idea. Just tested the code myself, all test cases seem to work just fine.
[deleted] 29 is working and returning weird.
bill_chan 29 is working fine for me. It is returning "weird" for me.
maheshkumar20101 29 is odd and it is weird .
ashpratap007 Even I was facing the same issue, problem with my code was, the wrong additional closing bracket after 6 in below line, maybe it happened due to autotyping:
(check[n%2==0 and (n in range(2,6))or n > 20])
Correct line, remove that additional bracket and add it after 20, then both the condition will be evaluated properly:
(check[n%2==0 and (n in range(2,6)or n > 20)])
ssachinsomane95 check your intendation
markohietala I have no idea what's happening there, but maybe that's why I'm learning this.
Diapolo10 I'll try my best to explain what's happening. :)
Line 1. We just take the input, remove any excess whitespace and store the integer in a variable.
Line 2. We define a dictionary, with boolean values as keys. If you didn't know this before, dictionaries can use any types as keys, not just strings! We are now using this to translate boolean values to strings.
Now, we ask Python to print something. We put the dictionary we just defined inside, and expect the program to print the value of the key we put in.
I've cut some corners here, because usually you would see a single variable inside those square brackets. I just didn't feel like adding an extra line, so I put the entire boolean expression instead.
Here comes the interesting part: first, we are checking if the input number is even. If it isn't, the expression will automatically return False, the dictionary outputs Weird and the print function prints the string on the console.
However, if the input number is indeed even, we then check if it's in the range from 2 to 6 or if it's more than 20. If either of these are true, the expression returns True, the dictionary outputs Not Weird and the said string is printed on the screen. If neither of these expressions are true, the expression returns False.
As for why I wrote the print function like that, I'd expect that to be more readable than a tight block of text. :p
markohietala That was an awesome answer! Now I fully understand :D Thank you for taking the time to explain this!
kmcdonal96 To summarise:
We're comparing user input to a set of conditions we've set out in our program. If the input matches the conditions, the program will print a message. A basic example of an if statement would be:
if (1 >= 0): return "Spam"
With regard to the question however, we're given multiple conditions and our program has to respond to those conditions as such. There are three outputs that expect a "Weird" output so we'll do a single if statement to address that
if (n in range (6, 21) or n % 2 != 0): return "Weird"
Firstly, we are saying if n is between the range of 6 and 21 (21 is not counted) print "Weird", we're also saying that if n is not an even number -- print the same result.
Lastly, we can just use an else statement to print off any remaining statements if none of test cases matched the previous conditions.
else: return "Weird"
And that's it, really. Best of luck!
faizu1992 short and good code !
AndrewNelsonJDM1 hey why the exclamation point? sorry in advance, noob.
Mixau If you write n % 2 == 0, you check if the remainder equals 0. When you write n % 2 != 0, you check if the remainder does not equal zero.
Diapolo10 And in layman's terms, n % 2 == 0 checks whether the number n is evenly divisible by 2 (or in other words, an even number) whereas n % 2 != 0 is the opposite, checking whether n is an odd number.
surajt_oneliner [deleted]sagarkp3 showing expected a indented block
yadavyogi003 I tried your code : if (n in range (6, 21) or n % 2 != 0): print("Weird") else: print("Not Weird")
its showing TypeError : not all arguments converted during string formatting
thomasokonkwo91 me too... I even tried running this on my own pycharm compiler and it worked. why is hackerrank compiler so different?
abhinavbahl51 to me it's showing invalid syntax.
Akshay807mirashe try n=int(input()) in python 3
7ankit4 n = int(input()) if(n>=1 and n<=100): if ((n % 2 != 0 or n>=6) and n<=20): print('Wierd') else: print('Not Wierd')
what is wrong in this code... I am getting the right output but failing the test case.koushikigupta01 because weird spelling is wrong in your code
jonh1521 At least from what I got it was getting an error when they tried it with "29" possibly due to it discarding it straight into your "else" condition due to being above 20. An elif between it solved it. n = float(input()) if 1 <= n <= 100: if (n % 2 != 0 or n >= 6) and n <= 20: print('Weird') elif n % 2 != 0: print("Weird") else: print('Not Weird')
pheepia7788 nice code!:)
tarunsankhla21 if instead of "or" condition should we put and condition so it can satisfy both
d_nadkarni Hi , In else it is suppose to be "Not Weird".Am i right?
ruedaesteban76 I am getting a Syntax error 'return' outside function. How can I fix that?
SyntaxError: 'return' outside function
[deleted] good work man!
KA_72 i think it should be in range(2,7)
manju_annure n = int(input('Enter the number:')) if (n % 2) == 0: if n in range(2,5): print ('Not weird') elif n in range(6,20): print ('weird') elif n > 20: print ('Not weird') else: print ('weird')
nikhilpshetty007 in elif it should be range(6,21), while running the loop it considers from 6 to 20.
SL170031111 if n%2!=0: print('Weird'); elif n%2==0 and 2<=n<=5: print('Not Weird'); elif n%2==0 and 6<=n<=20: print('Weird'); elif n%2==0 and n>20: print('Not Weird');
h170031054 wrong code onlyyyy..... u are foool onlyyyy....
sujeet_iiitm n = int(input()) if n%2!=0: print('Weird'); elif n%2==0 and 2<=n<=5: print('Not Weird'); elif n%2==0 and 6<=n<=20: print('Weird'); elif n%2==0 and n>20: print('Not Weird');
#it is right..mantasha_shakee1 but it fails in some test cases...
harikrish7373 it's works
sujeet_iiitm thx bro
balamuruganbrr good job bro
19amckinney thank you for this very helpfull information :)
fausto_ramirez Why is the range being checked between 2 and 6? Should it be 2 and 5 per the problem statement?
sudmic It is because the range method is inclusive for the lower bound while exclusive for the upper bound. For Example, range(2,5)= 2,3,4 while range (2,6)= 2,3,4,5. When using the range function, make sure you increase n by 1, i.e the upperbound be n+1.
crawlomkar Thanks for the great information!!! I am impressed Thanks & Best Regards
cupofchar Awesome explanation! Thank you so much! I was wondering though -- what is the difference between using a dictionary vs. if-else? Is it faster? More accurate? Should I be using a dictionary whenever I can? What cases would this be a good solution for? A bad solution?
akwin2171 Hey glad to hear you liked it...!! I am also learning and new to programming , so I try to make codes simple in a way every beginner can understand . As I believe you always have choice to write better codes but first one needs to understand it fully. Coming to your question using dictionary will be faster than using if-else. Moreover I would say if you are comfortable using dictionary at first use it , if it does'nt works on some cases then use if-else. Presently I am more comfortable using if-else so I used it.
akwin2171 Also here is a link if you wanna know more about your question's answer: https://stackoverflow.com/questions/11445226/better-optimization-technique-using-if-else-or-dictionary
aryankhandelwal2 this code is not work
bhargavipbc not working for me
aryankhandelwal2 i found my mistake in this code
aryankhandelwal2 i written the code in wrong manner i dont write else condition due to some my code error
geekyflow1423 Thanks for sharing this useful information with us. Make sure you have enough knowledge about com surrogate before considering it as a virus.
pnt31 why is it necessary to use the list comprehension [i for i in range(2, 6)] rather than just having the boolean expression n in range(2,6) ?
haisrilatha Even i have this doubt...
Diapolo10 It's not necessary, but this is the idea I first had. Of course I understand that list comprehensions are expensive and that they aren't supposed to be used like this, but the code still works.
JennyWenDE It's cool that you can try to solve on eproblem in many different ways. I mean the code above defeats the point but it's still really cool!!
n = int(input().strip()) check = {True: "Not Weird", False: "Weird"} print(check[ n%2==0 and ( n in range(2,6) or n > 20) ]) #Diapolo10 created this
Vincent007 [deleted]surajt_oneliner yeah please explain 'strip ()'
kylezs .strip() is a string method that by default removes any whitespace from either side of the whole string. e.g.
" hello there ".strip()
becomes "hello there"
If you add an argument, it will instead remove whatever characters you put as the argument from either side of the string (not the middle). You will often see it used like this, to clean up words after using .split():
import string word = "word!" word.strip(string.punctuation)
iamphanisai hey.. i am still a novice and i couldnt understand what you meant by "cleaning up words after using split".....i also couldnt understand the second snippet of code. Would u be kind enough to explain?.Thank you in advance
kylezs Try running the code yourself, it's the best way to learn. Also, in the terminal you can use the help('something') function, where you replace something with a built in function or type. For something like split() you need to use > help(str.split) since split is a string method.
"Cleaning up words" means removing punctuation and/or whitespace for words. This is useful if you want to count the number of words in a novel, so it doesn't count "word," as different to "word".
iamphanisai oh.thank you. will definetely try this out. Also which book would you prefer to learn python? i just completed the hard series by zed shaw
kylezs Zed Shaw is a good resource to get started (though I did it quite a while ago). Then maybe a different basics book because there a different styles of code etc. You should be able to fly through it if you already know most of it from Zed Shaw. Specifically Python For Everybody, which goes into the data handling side of Python, is quite good.
Then you have a few options. You can create programs of your choice, use Youtube, Stack Overflow etc. to learn each little part you might not know. Or, what I would recommend is spending a little bit of time on something like Hackerrank. Don't just write the program and pass the tests, look through what other people have done and make sure you can read and understand their approach. This way your programming rather than just your coding is improved. i.e. more efficient, cleaner etc.
Edit: I should add that I too am a student and by no means a professional! I made a few little programs and what not but I feel as though Hackerrank or Codefights or something is the best option for me at the moment, in order to improve my general programmatic thinking.
iamphanisai Thank you for taking the time in answering my question. Will do what you suggested (stackOverflow and youtube). By the way is it just me or does every beginner has the problem of forgetting the things he/she learned with the introduction of a new concept??;)
kylezs Definitely not just you!
JennyWenDE The is also a nice book called Learning Python the Hard Way. It costs money for actually book but you can read free online. https://automatetheboringstuff.com/
harshgulati this code cant' run on my laptop. . . . . .
JennyWenDE Try rebooting or closing some applicaton windows
mail2dinfo To remove space either side of string it slike ltrim in oracle
[DELETED] [deleted]
tharindupmadura1 In this code,why did you add a .strip()?Explain please
thomasokonkwo91 the purpose of the strip command is to remove white spaces.. for example:
print " hello world "
there are white spaces by the sides of hello world... but if you use the split command,
print (" hello world ").split()
it removes the white spaces at the beginning and the end.
also if you want to remove the white space the left, use .lstrip() and if its the right only, use .rstrip()...DO you understand it now ?
tharindupmadura1 yes.Thanks you very much
thomasokonkwo91 the purpose of the strip command is to remove white spaces.. for example:
print " hello world "
there are white spaces by the sides of hello world... but if you use the split command,
print (" hello world ").split()
it removes the white spaces at the beginning and the end.
also if you want to remove the white space the left, use .lstrip() and if its the right only, use .rstrip()...DO you understand it now ?
thomasokonkwo91 .strip() is used for removing white spaces at the end and at the beginning of your string. lets take for example,
print " hello world "
there white spaces at the beginning and the end... if we use the command, like this,
print (" hello world ").strip()
it removes the spaces and prints
hello world
also if you want to remove the white space at the left side only, use .lstrip() and at the right side only use .rstrip()
do you get it now ?
thieny1991 when you int to convert a string into a integer, int(str) will automatically remove '\n', so I don't think you need to use strip. Correct me if I am wrong.
satyakibose98 is it for python2 or python 3?
Diapolo10 Python 3. There's no chance of it working on Python 2 as well, because of the input() function; Python 2 uses raw_input().
xadageku I think It's Python 3 .. Help Sarkari
abinavjain807 Yes, it is Pyton 3 in my opinion too :) GeekSane
mikeastorry chapeau!
Venkat37 nice
iamphanisai i have to say this looks much more appealing than my 10 lines of if else code but can u tell me where does the checking whether n is between 1 and 100 is evaluated.? as it is one of the constraints. Thank you in advance
Diapolo10 There's no need to check if the given number is between 1 and 100; on the problem it reads that whatever numbers the site throws at your problem, they are never smaller than 1 or higher than 100.
Now, when it comes to the actual problem this hardly even matters; if you have done exactly as the problem specificaspecifications instructed, it can theoretically handle any integer. The reason the range of possible numbers is limited is because the ultimate point of this exercise isn't working with huge numbers, it's all about learning how to use if-elif-eif-elif-else.
That being said, nowhere in my code am I checking the validity of the input. In this environment, there's no need to.
i391658 [deleted]jstringer08 So many questions, but first....Why didn't my code work on this exercise? Now I know I probably chose a horrible Big O notation, but besides that I really thought it would have worked and I can't see why the application is failing me. Please explain becuase I want to understand. Thanks
num = int(input("Enter a number: ")) n = num % 2 if n == 0 and num >= 2 <=5: print('Not Weird') elif n == 0 and num >= 6 <=20: print('Weird') elif n == 0 and num > 20: print("Not Weird") elif n % 2 != 0: print('Weird')
franwhite A couple of things. 1) They don't seem to want anything in 'input', so get rid of 'Enter a number: '. 2) I think you've got your operators the wrong way round. 3) Should be 'num', not 'n' in the last bit. Try:
num = int(input()) n = num % 2 if n == 0 and (2<= num <=5): print('Not Weird') elif n == 0 and (6<= num <=20): print('Weird') elif n == 0 and num > 20: print("Not Weird") elif num % 2 != 0: print('Weird')
isadoralmeida06 you can simply do this for the last statement
elif n != 0: print('Weird')
sunthar317 Hi ,
if we use
""elif n ! = 0:"" and print ('weird')
will not give proper output .
It will give output "weird " for any even number above 20 . for instance try to give value as "22" it will retun "weird"
akwin2171 - n = int(raw_input())
- if n%2 == 0 and (2<= n <=5):
- print('Not Weird')
- elif n%2 == 0 and (6<= n <=20):
- print('Weird')
- elif n%2 == 0 and ( n> 20):
- print('Not Weird')
- elif n % 2 != 0:
- print('Weird')
secret_servers11 there is no need of strip() right
the_bowman Nice - this is a fun solution. My only comment would be being able to reduce the number of Boolean expression evaluations by one? Basically negate the second Boolean expression and invert the range.
n = int(input().strip()) check = {True: "Not Weird", False: "Weird"} print(check[n%2==0 and n not in range(6, 21)])
raovaishu Excellent approach dude !!
BobbyRusso33 Tha's a Weird solution.
xiaohuil n = int(input()) check = {True:'Weird',False:'Not Weird'} print (check[n%2 != 0 or n in range(6,21)]) This also worksSwastik_Ghosh [deleted]kushwahamukesh51 def odd_even(n): if n%2==0 and (n>=20): print 'Not Weird' elif n%2==0 and (2<=n<=5): print 'Not Weird' elif n%2==0 and (6<=n<=20): print 'Weird' else: print 'Weird' odd_even(24) why this give compiler error
Diapolo10 I don't know, this worked for me. (Python 3)
def odd_even(n): if n%2==0 and (n>=20): print("Not weird") elif n%2==0 and (2<=n<=5): print("Not weird") elif n%2==0 and (6<=n<=20): print("Weird") else: print("Weird") odd_even(24)
ppajce Very nice! I went step by step which is not as good:
n = int(input()) if n%2==1 : print("Weird") elif n%2==0 and 2<=n<=5 : print("Not Weird") elif n%2==0 and 6<=n<=20 : print("Weird") elif n%2==0 and n>20 : print("Not Weird")
boky_du Tnx i'll experiment with your code :D Can you explain .strip in more detail ?
Diapolo10 The
.strip()-part isn't actually necessary, asint()uses it internally anyway. But back when I wrote the code I didn't know that. :pIt's basically one of the methods defined by the
str-type; it removes all whitespace characters from the beginning and end of a string.Example:
my_string = " Hello " my_string.strip() == "Hello"
sai4ever perfect!
Ashish25 Hey that'is pretty nice, but failed to pass a compiler's test case, when I tried.
jatin_earth i'm sure you'll find this pretty neat.
n = int(raw_input()) if not(n%2==1 or n in range(6,21)): print "Not", print("Weird")
raamkishore_p You must put range(2,7) as the range function does not include the value in the second argument.
kiviengdpt Can't check with 3
geraldfeu I wish I was this good
nangtienca952000 [deleted]rnovoa2014 Bravo! Excellent!
pushkarsrawat there is a constraint of 1<= n <=100, and I believe this will fail in that test case if number is greater than 100
kakavegito77 i have a doubt .as i am a noob at python ..here
n in range(2,6)
also works and
n in range(2,5)
also works why's that ??
collincan Basically like a "switch/case" -- interesting
abhinavbahl51 I tried your code by removing strip function but it still worked fine. Why did you use strip function here?
mailshahidnasim to remove blank spaces if added from user
ashishpowani [deleted]romi04 I get this error
Traceback (most recent call last): File "solution.py", line 10, in n = int(input().strip()) AttributeError: 'int' object has no attribute 'strip'
Do you know why?nagarjunareddy82 Change the version to Python 3
mansi_sharma1231 really a great approach to this problem
j1548809 Or we can do like this without using a loop
***n=int(input("enter an integer:"))
mod=n%2
if mod!=0:
print("Weird")
if mod==0 and n>1 and n<=5:
print("Not Weird")
if mod==0 and n>5 and n<=20:
print("Weird")
if mod==0 and n>20:
print("Not Weird")
*
aleksandrhovhan1 I don't see how this is any more efficient than simple if-else statements. This uses more memory than you need to by unnecessarily mapping "true" to "not weird" and "false" to "weird". There's no point in doing that.
abhishekshivhar1 where is the constraint 1<= n <= 100
stevefang0585 What's the .strip for?
skay180 or the other way around:
n = int(input().strip()) check = {True: "Weird", False: "Not Weird"}
print(check[ (n%2!=0) or ((n%2==0) and n in range(6,21) ) ])
***made by diapolo10dgbaenar Great solution man :)
8astard8word You are a genius
cerutiriccardo I think you have to check negative number
sharathnetha1224 [deleted]norriskyle00 Stupid question(but I honestly don't know anything bout coding, first time really learning) but what's a boolean expression?
kabileshsivakum1 pls say y u have used .strip?? i cant understand it..
2016_rohit_dora1 Wow you have made it so simple
czglory awesome
hernandezjocely1 What are the trade offs of not using the boolean expressions? Is it faster? Does it make a code more efficiante? Just wondering :)
rahullata6789 hey why did you used strip fuunction for this code can u please explain me
thomasokonkwo91 The strip() method returns a copy of the string with both leading and trailing characters removed (based on the string argument passed). The strip() removes characters from both left and right based on the argument (a string specifying the set of characters to be removed).
In simple grammar, if one enters a value or any input and the person mistakenly press spacebar or leaves space, the strip function will clear out those spaces and pick up that character the person inputed only...
so lets say you enter " 5"... the space before the 5 will be removed with the strip function. I don't know if this helps
rahullata6789 Thanks a lot man.. I like the way you made me understand 😊❤️
thomasokonkwo91 hahaa.. you are welcome... I'm also new to programming. I explain as easy as i see it
Yas240 my code is working perfectly with all the conditions but the compiler kept saying wrong here is the code
dkrivic2 Love this answer.
reachmepriya N = int(input()) if ((N>0)and(N<101)): if(((N<6)or(N>20))and(N%2==0)): print("Not weird") else: print("Weird")
else: print("Out of boundary")
I executed the above one. It shows 3 testcases failed. Kindly clarify my doubts.
jordanatherton21 n = int(input().strip()) word = {True: "Not Weird", False: "Weird"} print(word[ n % 2 == 0 and (n in range (2, 7) or n > 21)])
it failed on me but fixed itself when fixing the ranges becasue 6 and 20 isnt read
i compared it to the if else statements i made if n % 2 == 0 and n in range (2, 7): print("Not Weird") elif n % 2 == 0 and n in range (7, 21): print("Weird") elif n % 2 == 0 and n > 20: print("Not Weird") elif n % 2 == 1: print("Weird")
risk_myself A W E S O M E bro
mohitsharma13511 what if input is 20
geekyflow1423 Thankyou for sharing this information with us. Textsheet
kavurugeethakal1 really its an amazing way of writing dis program thanks bro really it helped me a lot
ol03_I1Z print ('Not Weird', 'Weird')[n % 2 != 0 or 6 <= n <= 20]
rachitanayak I aspire to write code like this one day :)
developing_coder Equating True to Weird and False to Not Weird would reduce cognitive load when reading the code imo.
MrPaleSleazyWind weird_or_not = lambda n: 'Not '*(1-n % 2-(4 < n < 22))+'Weird'
shaurabh16101 why there is .strip() in input ??
kb_2578 Can some one please correct me. If I give input as 8 (or) 10, the output is 'NotWeird' instead of 'Weird'
n = int(input('Enter a number:')) if (n in range(2,6) or n in range(21,)) and (n%2==0): print('Not Weird') else: print('Weird')
neha_vathani_bi1 why is strip used here? what is its use?
btw... it is very simple, crisp and neat.
harindersahajpa2 This code won't work correctly. You should put n%2!=0 instead of n%2==0
yash_b2708 simply super broo.
hichamamchtk Nice one, thanks for sharing
dmachibya fantastic!
srivastavadevan1 Thanks for this method
hexenvexen Thanks for the gold, kind stranger!
pateljahnavi72 Hey, but you haven't included the constraints i.e. range of n is 1-100. And another thing is when I submitted my code including them, it is failing one of the test cases and working fine without the constraint.
TheCodeHere I am pretty proud of my code, i think this is the best option:
n = int(raw_input()) if n%2==0 and (n in range(2,6) or n>20 ): print "Not", print "Weird"
parisa_payami Nice ^__^
thomasokonkwo91 why did you add the comma after the print "Not" ?
david_palmer1 The next print will be added on the same line as the comma.
lucasisaacbr if __name__ == '__main__': n = int(raw_input()) if n % 2 != 0 or n > 5 and n < 21 : print("Weird") else: print("Not Weird")
jordanofreitas Simples e objetivo!
rajarshi356 if name == 'main': What's the significance of this line ?
consumed Python uses this to determine whether the script is being run as the main script or being run as a module. So you can define different actions for your script based on the condition it is run.
rajarshi356 Thnx alot
johnrobertforbes My solution :),
if __name__ == '__main__': n = int(input()) print(("Not " if n%2==0 and (n<=4 or n>20) else "") + "Weird")
Ugaga if N in range(6,21) or N%2!=0: print("Weird") else: print("Not Weird")
muraveilnx [deleted]muraveilnx n = int(input()) if n % 2 != 0 or 6 <= n <= 20: print ("Weird") else: print ("Not Weird")
askarovdaulet Even shorter :)
print('Weird' if n%2==1 or 6<=n<=20 else 'Not Weird')
brianjoramwando1 goodOne,
that's how amazing python is. I had written 8 lines of code
Jitender98 Question specifically asks to use "If-Else",So I did.
n = int(input()) if n % 2 == 0: if n in range(2,6): print("Not Weird") elif n in range(6,21): print("Weird") elif n > 20: print("Not Weird") else: print("Weird")
lahouari Hi hackers
if __name__ == '__main__': n = int(input()) if n & 1 == 1: print('Weird') elif n > 2 and (n <= 5 or n > 20): print('Not Weird') else: print('Weird')
rajyavardhan1 why is n &1==1 needed
hyrlammiranda I dont understand why you put n & 1 == 1 Can you explain to me please? I was thinking if I put if n > 1 and n <= 5 can work too right? I just start python now so sometimes I dont understand.
lahouari I only followed the problem conditions:
if n is odd
if n & 1 == 1:
if n is even and is within ranges
elif ...:
otherwise
else ...:
pranaygarlapati Why dont u replac if n&1==1 as if n%2!=0 print ('weird')
padmarao_gpr Try this easy starting time
n=int(input("Enter integer:")) if (n%2!=0 or (n>=6 and n<=20)): print ("Weird") elif(n>=2 and n<=5 or n>20): if (n%2==0): print ("Not Weird")
padmarao_gpr [deleted]Nbah07 It's a boolean expression, no? I didn't understand the outcome of it as well. n AND 1 == 1 ? What is the convention for 'n' be True?
camozzi It's a bitwise operator.
https://stackoverflow.com/questions/16382403/how-to-judge-a-int-number-odd-or-even-the-binary-way
liuqing5524 It is very readable,thanks!
kalyanrokzz n = int(input()) if n%2!=0: print("Weird") elif n%2==0 and n in range(2,5): print("Not Weird") elif n%2==0 and n in range(6,20): print("Weird") elif n%2==0 and n >20: print("Not Weird") else: print("Weird")
marinskiy Here is Python solution from my HackerrankPractice repository:
def wierd(n): if n % 2 == 1 or 6 <= n <= 20: print('Weird') else: print('Not Weird') wierd(int(input()))
Feel free to ask if you have any questions :)
rb00795400 n = int (input()) if n %2 == 1 or n >= 6 and n <= 20: print('Werid') else: print('Not Werid') sir its my code but compiler gave worng answer
tricerabottoms print((lambda a:{1:"Weird",0:"Not Weird"}[a%2 or 5<a<21])(int(input())))
ankit_kumar_cs Complex code
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