aproftr a = int(input()) b = int(input()) print('{0} \n{1} \n{2}'.format((a + b), (a - b), (a * b)))
Shashikanth_Bag1 Its Correct One ~!!
& Nice Coding :-)
0xdeadfeed a,b = int(input(),int(input()) print('{0} \n{1} \n{2}'.format((a + b), (a - b), (a * b)))
bryon_nicoson I did this as follows, and it passed all test cases, but I am wondering about proper formatting. Should I have enclosed format calculations in parens? Should I have used 0,1,2 instead of generic :d?
print('{:d}\n{:d}\n{:d}'.format(a+b,a-b,a*b))
digvijayyadav48 what exactly does this line mean?
arkodeep01ghosh this is known as string fomating in python which literally is just putting the respective valies in their respective places
aam3r77 what is generic ?
arkodeep01ghosh yes or u could have left it blank
pengyue wow,cool
sainagarajusakh1 nice code and what is the use of "format"
bryon_nicoson import math print 'The value of {label} is approximately {0:.3f}.'.format(math.pi, label='PI')
output: "The value of PI is approximately 3.142."
There are several more examples of str.format here: Python 2 Input & Output
faizmd The format() method of string is useful in specifying a string in the format you wish. {0},{1} and {2} are positional parameters (like indices in an array). So {0} is assigned the value of a+b, {1} is assigned the value of a-b and {2} is assigned the value of a*b.
You can also use keyword paramters instead of positional parameters in format(). Eg: print("My name is {name}".format(name="faiz")). Here 'name' is the keyword and the value of name is 'faiz'
EL_Kaito a = int(input()) b = int(input()) print("%d\n%d\n%d"%(a+b,a-b,a*b))
Is there any difference in terms of performance?
shreshta38 What is the significance of "%d" and % before printing the values
dacdongdhv that name is a string (%s) and number is an integer (%d for decimal). See https://docs.python.org/3/library/stdtypes.html#printf-style-string-formatting for details
austindholmes [deleted]
NAMRATA1712 its showing a run time error
mssundar005 [deleted]ram031197 Its really simple :)
cavad_salamov994 '{0} \n{1} \n{2}' -what is the meaning of this brackets? -when we generally use this method ?
motorolamarcin You can even skip passing numbers into curly brackets
print("{}\n{}\n{}".format(a+b, a-b, a*b))sudhansudwivedi1 what about the constraints??
tury160391 The print statement is great but what if I input 2.5x10^11? Isn't there a missing checking?
marinskiy Here is Python solution from my HackerrankPractice repository:
a, b = int(input()), int(input()) print((a + b), (a - b), (a * b), sep='\n')
Feel free to ask if you have any questions :)
avadheshyadav175 this code returns o/p as: 325 1 6 if take i/p (3,2)
marinskiy Please, check again. It returns correct output: 5, 1, 6
prince951 What does (sep ='\n') do?
avadheshyadav175 (sep='\n') will display the outputs in new
marinskiy It starts a new line after each number
dattatreya_badi1 seperate each answer by next line
if sep=',' then each answer will be separated by a comma
d7d77d7d77 why this is not working print(a+b) print(a-b) print(a* b)
spoorthi_m I believe you can run this only on Python 3.
kukeshkumar007 sep='\n' (i want to know about this).
Faker88Si Python 3
if __name__ == '__main__': a = int(input()) b = int(input()) print (a+b) print (a-b) print (a*b)
stivodivos my first expected value a+b comes up as 325, why?
a = int(raw_input(3)) b = int(raw_input(2)) print a+b print a-b print a*b
Your Output (stdout) 325 1 6
carlamarrow I experienced the same output. So I decided to see what it thought 'a' was:
a=int(raw_input(3)) b=int(raw_input(2)) print(a) print(a+b) print(a-b) print(a*b) print(a)
And got: 323 5 1 6 3
So, why does the first iteration of 'a' believe it is 323?
carlamarrow Ok, I figured it out. When you try to use static values it results in the 325 1 6. Example of static values 3 & 2: a=int(raw_input(3)) b=int(raw_input(2)) etc...
When I remove the static values then the process works:
a=int(raw_input()) b=int(raw_input()) etc...
I assume the input values (3, 2) are provided as part of the test case when executed.
amnaalali what do you mean by remove static values, Im having the same issue
sylie Its not because of static values .Its because the Python work on REPL i.e, R - Read E - Execute P - Print L - Loop So here when a = raw_input(3) is given it Reads the command, Execute it i.e takes a as input 3, Prints it i.e why it prints 3 and then 2 for b = raw_input(2) and then Loop back again i.e it waits to read next instruction. Hence your output is like 325 1 6
webnerdie moreover Python considers your inputs as strings and they're concatenated when you don't convert them explicitly. That's why you get such errors.
munish01211 you don't have to provide the values while declaring the variable. It will be provided by the program during compile time.
So the code would be:
a=input() b=input() print (a+b)
faizmd i guess it is because of raw_input() which cconsiders the console input as string and your program is doing string concatenation.
VishnuKarnam The argument inside raw_input("argument") will print the argument on the console.
thetoretto1 Since version 3.6 Python have got f-strings "formatted strings" so it's as easy as this:
print(f"{a+b}\n{a-b}\n{a*b}")
akarsu_ufuk a = int(input()) b = int(input()) print(a+b,a-b,a*b, sep="\n")
tiagostaurenghi for i in [a+b, a-b, a*b]: print(i)
wasiahmed049274 a = int(raw_input()) b = int(raw_input()) def do_it_all(fn): def poll(*args, **kwargs): return fn(*args, **kwargs) return poll def add(a, b): return a + b def sub(a, b): return a - b def mul(a, b): return a * b add = do_it_all(add) print(add(a, b)) sub = do_it_all(sub) print(sub(a, b)) mul = do_it_all(mul) print(mul(a, b))
apurv_mishra41 if name == 'main':
what does this line mean? Can anyone please explian?
tung_nn83 the constrains of a and b must be from 1 to 10**10, why the values input of the second test case are: 6564424525 and 323252462
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