aproftr a = int(input()) b = int(input()) print('{0} \n{1} \n{2}'.format((a + b), (a - b), (a * b)))
Shashikanth_Bag1 Its Correct One ~!!
& Nice Coding :-)
0xdeadfeed a,b = int(input(),int(input()) print('{0} \n{1} \n{2}'.format((a + b), (a - b), (a * b)))
bryon_nicoson I did this as follows, and it passed all test cases, but I am wondering about proper formatting. Should I have enclosed format calculations in parens? Should I have used 0,1,2 instead of generic :d?
print('{:d}\n{:d}\n{:d}'.format(a+b,a-b,a*b))
pengyue wow,cool
sainagarajusakh1 nice code and what is the use of "format"
bryon_nicoson import math print 'The value of {label} is approximately {0:.3f}.'.format(math.pi, label='PI')
output: "The value of PI is approximately 3.142."
There are several more examples of str.format here: Python 2 Input & Output
faizmd The format() method of string is useful in specifying a string in the format you wish. {0},{1} and {2} are positional parameters (like indices in an array). So {0} is assigned the value of a+b, {1} is assigned the value of a-b and {2} is assigned the value of a*b.
You can also use keyword paramters instead of positional parameters in format(). Eg: print("My name is {name}".format(name="faiz")). Here 'name' is the keyword and the value of name is 'faiz'
EL_Kaito a = int(input()) b = int(input()) print("%d\n%d\n%d"%(a+b,a-b,a*b))
Is there any difference in terms of performance?
shreshta38 What is the significance of "%d" and % before printing the values
dacdongdhv that name is a string (%s) and number is an integer (%d for decimal). See https://docs.python.org/3/library/stdtypes.html#printf-style-string-formatting for details
NAMRATA1712 its showing a run time error
mssundar005 [deleted]ram031197 Its really simple :)
cavad_salamov994 '{0} \n{1} \n{2}' -what is the meaning of this brackets? -when we generally use this method ?
marinskiy Here is Python solution from my HackerrankPractice repository:
a, b = int(input()), int(input()) print((a + b), (a - b), (a * b), sep='\n')
Feel free to ask if you have any questions :)
avadheshyadav175 this code returns o/p as: 325 1 6 if take i/p (3,2)
marinskiy Please, check again. It returns correct output: 5, 1, 6
prince951 What does (sep ='\n') do?
avadheshyadav175 (sep='\n') will display the outputs in new
marinskiy It starts a new line after each number
dattatreya_badi1 seperate each answer by next line
if sep=',' then each answer will be separated by a comma
d7d77d7d77 why this is not working print(a+b) print(a-b) print(a* b)
stivodivos my first expected value a+b comes up as 325, why?
a = int(raw_input(3)) b = int(raw_input(2)) print a+b print a-b print a*b
Your Output (stdout) 325 1 6
carlamarrow I experienced the same output. So I decided to see what it thought 'a' was:
a=int(raw_input(3)) b=int(raw_input(2)) print(a) print(a+b) print(a-b) print(a*b) print(a)
And got: 323 5 1 6 3
So, why does the first iteration of 'a' believe it is 323?
carlamarrow Ok, I figured it out. When you try to use static values it results in the 325 1 6. Example of static values 3 & 2: a=int(raw_input(3)) b=int(raw_input(2)) etc...
When I remove the static values then the process works:
a=int(raw_input()) b=int(raw_input()) etc...
I assume the input values (3, 2) are provided as part of the test case when executed.
amnaalali what do you mean by remove static values, Im having the same issue
sylie Its not because of static values .Its because the Python work on REPL i.e, R - Read E - Execute P - Print L - Loop So here when a = raw_input(3) is given it Reads the command, Execute it i.e takes a as input 3, Prints it i.e why it prints 3 and then 2 for b = raw_input(2) and then Loop back again i.e it waits to read next instruction. Hence your output is like 325 1 6
webnerdie moreover Python considers your inputs as strings and they're concatenated when you don't convert them explicitly. That's why you get such errors.
munish01211 you don't have to provide the values while declaring the variable. It will be provided by the program during compile time.
So the code would be:
a=input() b=input() print (a+b)
faizmd i guess it is because of raw_input() which cconsiders the console input as string and your program is doing string concatenation.
VishnuKarnam The argument inside raw_input("argument") will print the argument on the console.
Faker88Si Python 3
if __name__ == '__main__': a = int(input()) b = int(input()) print (a+b) print (a-b) print (a*b)
Ciberexplosion a = int(input()) b = int(input()) print('%s\n%s\n%s'%((a+b,(a-b),(a*b))))
pstarliu Also how come support python2 only, not python3
shashank21jHackerRank Admin How does it matters? it's the same code.
Btw, it's intended to be tutorial for Python2 , after that it's expected from you to see python3 syntax.tjgerot Actually, its because the method "raw_input" was deprecated in Python 3. That's why the first Python excercise (without raw_input) gave you the choice of Python 2 or Python 3. In Python 3, raw_input was replaced with the basic input() method. These excercises, if done with Python 3, would either make you classify and convert the input to a boolen, int, float etc. because input() always produces a string, or the excercises would require you to go in depth and use the sys module to read from system input.
kmcdonal96 Another thing, you can use Python3. You just need to switch it from Python2 to Python3 in the editor!
mtrp12 Attempt at one liner solution:
(lambda a, b : print((a + b), (a - b), (a * b), sep="\n"))(int(input()), int(input()))
//inspired by marinskiy
keshavgarg400 how can we print it in single print statement like--. print(a+b,"\n",a-b,"\n",a*b)
sakibhasan2263 Lengthy easier solution for ..ultra begginners like me :P
a = int(input()) b = int(input()) print(a+b) print print(a-b) print print(a*b)
pdoddOG a = int(input()) b = int(input()) x1 = (a + b); x2 = (a - b); x3 = (a * b);print(x1) print(x2) print(x3)
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