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  1. Practice
  2. Python
  3. Introduction
  4. Python: Division
  5. Discussions

Python: Division

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  • sarbazx + 5 comments
    print("{0}\n{1}".format(a//b, a/b))
    • chethanhquang + 2 comments

      what is the point of adding the "{0}\n{1}".format

      • sarbazx + 0 comments

        {0} is replaced by a result of a//b see docs for format()

      • Bucci + 0 comments

        It's string interpolation using .format() it's useful because it's only one call to the print function instead of 2.

    • collincan + 0 comments
      print("{}\n{}".format(a//b, a/b))

      Does work as well

    • shubhie267 + 1 comment

      doesnt work for me

      • nadeem179ali + 0 comments

        It works.

    • mehdi_mirhashemi + 0 comments

      nice job ;)

    • chaitrali_palas1 + 0 comments

      why cant I use- print(a//b) print(a/b)

  • marinskiy + 2 comments

    Here is Python 3 solution from my HackerrankPractice repository:

    a, b = int(input()), int(input())
print(a // b, a / b, sep='\n')

    Feel free to ask if you have any questions :)

    • uday_boyanapalli + 3 comments

      I did write my code like this. but it did'nt work. So I had to print as seperate. print(a//b) print(a/b)

      • itsjaiwal + 1 comment

        why this sep keyword use...

        • marinskiy + 0 comments

          "sep" means separator. In this case sep='\n' means that two numbers are separated by end of line character. In other words, second number will be printed on a new line

      • adityakakade16 + 1 comment

        seperate does not work in case of a integer

        • marinskiy + 0 comments

          I dont think that is correct. However, sep does not work in Python 2

      • marinskiy + 0 comments

        This is a Python 3 solytion. You need to check "Python 3" in this box:

        Print does not have a sep argument in Python 2.

    • deepika121 + 0 comments

      how we will get can you explain

  • vinithvinu07 + 3 comments

    I have tried this, Passed all test cases

    print((a//b),(a/b),sep='\n');

    • pavankalyan_nv + 1 comment

      But It's not working for me

      • bryon_nicoson + 0 comments

        it is a python 3 print statement - won't work in python 2 - sarbazx print.format below is good solution.

    • h18224435984 + 1 comment

      six six six

      • xiaodanluckydog + 0 comments

        I bet you are a Chinese. 666

    • samyutha90 + 3 comments

      What is mean by sep='\n'??

      • monstermojo133 + 0 comments

        mean seperated by a new line

      • 8806995906a + 0 comments

        "\n " this is for new line

      • Satishpal456 + 0 comments

        here we seperate our result with \n means new line

  • shantanu_sharma1 + 1 comment

    def arithmatic(x,y): print (int(x//y)) print (float(x)/float(y))

    x=float(raw_input()) y=float(raw_input()) arithmatic(x,y)

    • mubarakperks2 + 0 comments

      a=input() b=float(input()) print a//b

  • bill110lr + 0 comments

    Thought I'd give variable names to the calculations

    intdiv = a//b
floatdiv = a/b
print ("{0}\n{1}".format(intdiv, floatdiv))

  • tamim_hamoudi + 0 comments
    print('{:d}\n{:0f}'.format(a//b, a/b))

  • av_shukla17 + 0 comments

    print round(a/b) print a/b

  • jacomeanthony13 + 0 comments

    a = int(raw_input()) b = int(raw_input())

    print a + b print float(a) / b

    I get the same answer as the solution why does it say im wrong?

  • rebollo_felipe92 + 0 comments
    # Python3
print("{}\n{}".format(a//b, a/b))

  • scbutters + 0 comments

    Is there a simpler way?

    print(a//b, a/b, sep='\n')
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