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  1. Practice
  2. Python
  3. Introduction
  4. Python: Division
  5. Discussions

Python: Division

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  • sarbazx + 5 comments
    print("{0}\n{1}".format(a//b, a/b))
    • chethanhquang + 2 comments

      what is the point of adding the "{0}\n{1}".format

      • sarbazx + 0 comments

        {0} is replaced by a result of a//b see docs for format()

      • Callat + 0 comments

        It's string interpolation using .format() it's useful because it's only one call to the print function instead of 2.

    • collincan + 1 comment
      print("{}\n{}".format(a//b, a/b))

      Does work as well

      • gene_carter + 0 comments

        no

    • shubhie267 + 1 comment

      doesnt work for me

      • nadeem179ali + 0 comments

        It works.

    • mehdi_mirhashemi + 0 comments

      nice job ;)

    • chaitrali_palas1 + 2 comments

      why cant I use- print(a//b) print(a/b)

      • anaghalokhande29 + 0 comments

        I used it, and worked for me.

      • ellin33 + 0 comments

        This worked for me as well. Just print in seperate lines.

  • marinskiy + 2 comments

    Here is Python 3 solution from my HackerrankPractice repository:

    a, b = int(input()), int(input())
print(a // b, a / b, sep='\n')

    Feel free to ask if you have any questions :)

    • uday_boyanapalli + 3 comments

      I did write my code like this. but it did'nt work. So I had to print as seperate. print(a//b) print(a/b)

      • itsjaiwal + 1 comment

        why this sep keyword use...

        • marinskiy + 0 comments

          "sep" means separator. In this case sep='\n' means that two numbers are separated by end of line character. In other words, second number will be printed on a new line

      • adityakakade16 + 1 comment

        seperate does not work in case of a integer

        • marinskiy + 0 comments

          I dont think that is correct. However, sep does not work in Python 2

      • marinskiy + 0 comments

        This is a Python 3 solytion. You need to check "Python 3" in this box:

        Print does not have a sep argument in Python 2.

    • deepika121 + 0 comments

      how we will get can you explain

  • vinithvinu07 + 3 comments

    I have tried this, Passed all test cases

    print((a//b),(a/b),sep='\n');

    • pavankalyan_nv + 1 comment

      But It's not working for me

      • bryon_nicoson + 0 comments

        it is a python 3 print statement - won't work in python 2 - sarbazx print.format below is good solution.

    • h18224435984 + 1 comment

      six six six

      • xiaodanluckydog + 1 comment

        I bet you are a Chinese. 666

        • newman2003 + 0 comments

          illuminati confirmed

    • samyutha90 + 3 comments

      What is mean by sep='\n'??

      • monstermojo133 + 0 comments

        mean seperated by a new line

      • 8806995906a + 0 comments

        "\n " this is for new line

      • Satishpal456 + 0 comments

        here we seperate our result with \n means new line

  • coder_aky + 0 comments

    100% working ,Simple and easy :-)

    Here's Python 3 one liner.....

    a,b=int(input()),int(input());print(a//b,a/b,sep='\n')

  • shantanu_sharma1 + 1 comment

    def arithmatic(x,y): print (int(x//y)) print (float(x)/float(y))

    x=float(raw_input()) y=float(raw_input()) arithmatic(x,y)

    • mubarakperks2 + 0 comments

      a=input() b=float(input()) print a//b

  • amrit_ayshwar + 0 comments

    print("%d\n%.11f"%(int(a//b),float(a/b)))

  • ayush_pandey2000 + 0 comments

    result=a/b print(int(result)) print(float(result))

    it works for me.

  • chahidi_h + 0 comments

    please, i would like to know difference between {:d} and {:0} representation

  • Kesharwani_supr1 + 0 comments

    print(a//b) print(a/b)

  • al1609073 + 0 comments

    This works for me: print(a//b) print(a/b)

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