wuestenblume Thought my solution turned out looking pretty good so I thought I'd share:
print(*[num**2 for num in range(n)], sep='\n')
surfer2047 How does print(*[list]) works, could you please tell.
rpepato This is an arbitrary argument list. It works by expanding a list into a sequence of positional parameters by using the * operator. Take a look at this examples at the python tutorial.
nthomas1999 Beautiful. You taught me something today. Thanks
Canas Though I like your solution (great use of unpacking), I think this is just more straightforward
[print(i**2) for i in range(n)]
arpita0116 why the square bracket ?
Canas The square bracket in this case corresponds to a List Comprehension in Python. They're neat for many reasons, but for this particular case it's mostly a better looking (and probably faster) for-loop.
arpita0116 Got it. Thanks
maheswaradito youu using python 2 or 3
shankarmurthy88 where is that square bracket?
chadwalt FROM THIS:
counter = 0; while counter < n : print (counter**2) counter = counter + 1
TO THIS:
[print(i**2) for i in range(n)]
Thanks alot for that link
Lukewardly I would have said, from this:
for i in range(n): print(i**2)
To the following code
kumarparth123 ME TOO GETTING ERROR PLEASE HELP
nick3499 [deleted]kumarparth123 its working thanks.
kumarparth123 one more doubt are last five topics waste in hacker rank python
nick3499 [deleted]namanbhoj99 using python 3
n = int(input())
for i in range(0,n): print(i*i) i= i+1
pratik15045569 no need to write i=i+1 . otherwise its perfect.
rupeshjawadwar File "solution.py", line 4 [print(i**2) for i in range(n)] ^ SyntaxError: invalid syntax
Getting error please help
nikhilnsr1998 i hope you got it by now, but the square brackets are at the wrong position... here we are printing a list ------->(unpacking) list : i**2 for i in range(n) where i iterates over the provided range and i**2 is computed out Syntax:
a=[i**2 for i in range(N)] print(a)
or in one line: print([i**2 for i in range(N)])
thomasokonkwo91 if __name__ == '__main__': n = int(raw_input()) i=0 for i in range(n): print pow(i,2)
karan_katam16 why i=0?
ashishfrancis291 This is the only thing that helped me because the output was not required in the list format. Thankyou so much !
DahliaSR No it is not, this means, that print() will be called n-times instead of once.
Besides that you need to keep in mind that any function or method in python always returns None unless it is told explicitly to return something else. In your solution, the list comprehension will return a list of length n, where each item is None.
>>> n = 5 >>> [print(i**2) for i in range(n)] 0 1 4 9 16 [None, None, None, None, None]h150303105219 how to get output for testcase 1 result
bryon_nicoson it is an elegant python 3 solution
adocto01 When testing with input 21 I get 21 lines of output which violates the constraints as it's supposed to limit N to between 1 and 20. I'm kind of confused because I'm not sure whether the Problem's constraints mean we're supposed to restrain inputs to that range in the program or if the end user of the program will restrain their inputs to that range.
b0kater This refers to the test cases that hackerrank will use to check your work. The constraints state "our test data will fit these constraints."
nick3499 [deleted]
engr_ravijain thanks you thaught me something new and usefull
ic3balandran The problem was about loops. If you show that to a beginner most likely they will not understand.
The solution with loops is just as short.
for i in range(0, n): print(i * i)
DahliaSR This approach, would fail!
The exponent has to be 2 and not i.chris_m_sullens That's not an exponent: i*i = i**2
namanbhoj99 buT it only prints 0 and n squared
vnsst123 Yes sir. I am a beginner and was searching for this kind of a one. Thank you
huanyu_liao it seems that py2 doesn't support this syntax
DahliaSR Replace the list comprehension by a generator expression and you got the most efficient and shortest solution.
Lehonti Nice solution! How about using iterators instead of arrays? It's more memory-efficient
print(*(num**2 for num in range(n)), sep='\n')
sunnyjagtap23_sj error.......
Ashish25 Thanks for teaching argument unpacking along with list comprehension.
twistagent hey thats pretty good
sfasu77 Awesome, blows my solution away lol
ram031197 Why * is used in print statement
ElFernando This is my solution papus
n=int(input())
for i in range(n):
print(i**2)karthikeyan1204 try for i in range(0,n):
ElFernando It's a same! range(0,n) that range(n):
KavinRanawella this is working right?
namansharma0206 N=int(input()) for i in range(N): print(i**2) This one works
pkhadka56 I don't know why test case 1 keeps on failing.
PRASHANTB1984 Do take a look at the successful submissions on the leaderboard!
eng_shomer how to know the successful submission
pkhadka56 okay
Sowbarani n = int(raw_input()) for i in range(0,n): print i*i
while compiling the above code its showing the IndentationError, Why its occuring ? Can any one help on this ?
Sorry: IndentationError: expected an indented block (solution.py, line 3)
merrdem for py3
x = int(input())
if x<=20 and x>=0:
for a in range(0,x): print(a**2)Sonalj getting an error in this
merrdem x = int(input()) if x<=20 and x>=0: for a in range(0,x): print(a**2)
it is working mate
munishsinghdanu1 [deleted]
munishsinghdanu1 in python 2 use
for a in range(0,x): if x>=0 and x<=20: print (a**2)
StorenthCatena python2 print without ()
dkapuriya99 Brother why we need to take new letter "a"? (for a in range(0,x):) can you explain? Thank you
shivamnamdeo43 Can someone tell me why I am getting error while submission on below code ?
N=5 if N >= 1 and N <= 20: for i in range(0,N): print(i ** 2)
norriskyle00 Total newbie status but am confused about the problem itself, loops, and how to implement the integers(1
sandy_aquarius90 Simplest solution -
for i in range(0,n): print(i*i)
richdad_solomon If you enjoy using map and lambda, check this out:
print(*map(lambda x: x**2, range(n)), sep='\n')
9999Rish print ('This one is the easiest') n = int(input()) for i in range(n): print(i**2)
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