tarathedev Thought my solution turned out looking pretty good so I thought I'd share:
print(*[num**2 for num in range(n)], sep='\n')
surfer2047 How does print(*[list]) works, could you please tell.
rpepato This is an arbitrary argument list. It works by expanding a list into a sequence of positional parameters by using the * operator. Take a look at this examples at the python tutorial.
nthomas1999 Beautiful. You taught me something today. Thanks
Canas Though I like your solution (great use of unpacking), I think this is just more straightforward
[print(i**2) for i in range(n)]
arpita0116 why the square bracket ?
Canas The square bracket in this case corresponds to a List Comprehension in Python. They're neat for many reasons, but for this particular case it's mostly a better looking (and probably faster) for-loop.
arpita0116 Got it. Thanks
maheswaradito youu using python 2 or 3
sweaze Thanks for the explanation.
shankarmurthy88 where is that square bracket?
chadwalt FROM THIS:
counter = 0; while counter < n : print (counter**2) counter = counter + 1
TO THIS:
[print(i**2) for i in range(n)]
Thanks alot for that link
Lukewardly I would have said, from this:
for i in range(n): print(i**2)
To the following code
kumarparth123 ME TOO GETTING ERROR PLEASE HELP
nick3499 [deleted]kumarparth123 its working thanks.
kumarparth123 one more doubt are last five topics waste in hacker rank python
nick3499 [deleted]namanbhoj99 using python 3
n = int(input())
for i in range(0,n): print(i*i) i= i+1
pratik15045569 no need to write i=i+1 . otherwise its perfect.
imsd_14 This will Work
i =0;
while i < n: print(i**2) i = i + 1
rupeshjawadwar File "solution.py", line 4 [print(i**2) for i in range(n)] ^ SyntaxError: invalid syntax
Getting error please help
nikhilnsr1998 i hope you got it by now, but the square brackets are at the wrong position... here we are printing a list ------->(unpacking) list : i**2 for i in range(n) where i iterates over the provided range and i**2 is computed out Syntax:
a=[i**2 for i in range(N)] print(a)
or in one line: print([i**2 for i in range(N)])
thomasokonkwo91 if __name__ == '__main__': n = int(raw_input()) i=0 for i in range(n): print pow(i,2)
karan_katam16 why i=0?
ashishfrancis291 This is the only thing that helped me because the output was not required in the list format. Thankyou so much !
somya_r_panda Is this list comprehension??
DahliaSR No it is not, this means, that print() will be called n-times instead of once.
Besides that you need to keep in mind that any function or method in python always returns None unless it is told explicitly to return something else. In your solution, the list comprehension will return a list of length n, where each item is None.
>>> n = 5 >>> [print(i**2) for i in range(n)] 0 1 4 9 16 [None, None, None, None, None]h150303105219 how to get output for testcase 1 result
bryon_nicoson it is an elegant python 3 solution
yingning600 Could you please explain what (i**2) means?
chaitanya215 "**" means to the power of (exponential). here it means i * i
chaitanya215 but n is a integer right? what is meant by 'range(n)'
adocto01 When testing with input 21 I get 21 lines of output which violates the constraints as it's supposed to limit N to between 1 and 20. I'm kind of confused because I'm not sure whether the Problem's constraints mean we're supposed to restrain inputs to that range in the program or if the end user of the program will restrain their inputs to that range.
b0kater This refers to the test cases that hackerrank will use to check your work. The constraints state "our test data will fit these constraints."
nick3499 [deleted]
engr_ravijain thanks you thaught me something new and usefull
ic3balandran The problem was about loops. If you show that to a beginner most likely they will not understand.
The solution with loops is just as short.
for i in range(0, n): print(i * i)
DahliaSR This approach, would fail!
The exponent has to be 2 and not i.chris_m_sullens That's not an exponent: i*i = i**2
namanbhoj99 buT it only prints 0 and n squared
vnsst123 Yes sir. I am a beginner and was searching for this kind of a one. Thank you
huanyu_liao it seems that py2 doesn't support this syntax
DahliaSR Replace the list comprehension by a generator expression and you got the most efficient and shortest solution.
Lehonti Nice solution! How about using iterators instead of arrays? It's more memory-efficient
print(*(num**2 for num in range(n)), sep='\n')
nikhilproject1 why did you use " sep='\n' ". codes works without it
arsh_suri and what about the start after print. why is that used
sunnyjagtap23_sj error.......
Ashish25 Thanks for teaching argument unpacking along with list comprehension.
twistagent hey thats pretty good
sfasu77 Awesome, blows my solution away lol
ram031197 Why * is used in print statement
m_balasubramani1 Nice bro.. helped me in another problem. You've used 'sep' as an argument to the print statement. Is it defined somewhere? Could you pls clarify?
maxmarinibastos How does 1<=N<=20 in your code?
amrut05 why haven't you considered the constraint 1<=N<=20?
nihapandey113 "ValueError: invalid literal for int() with base 10: '' I am getting this error even after using your solution in Python 3. Can u please let me know whats the issue here
cristinamais2 Omg, I tried so many times until seeing your solution. Thank you.
kalyan_prsd It seesm an in valid syntax. Please check!
deepakyadav880 [deleted]ranjithkjagadis1 Awesome dude...
17h51a04c1 what is sep ?
ElFernando This is my solution papus
n=int(input())
for i in range(n):
print(i**2)karthikeyan1204 try for i in range(0,n):
ElFernando It's a same! range(0,n) that range(n):
KavinRanawella this is working right?
namansharma0206 N=int(input()) for i in range(N): print(i**2) This one works
pkhadka56 I don't know why test case 1 keeps on failing.
PRASHANTB1984 Do take a look at the successful submissions on the leaderboard!
eng_shomer how to know the successful submission
pkhadka56 okay
knock320 I don't understand the obective. What is the obective?
Sowbarani n = int(raw_input()) for i in range(0,n): print i*i
while compiling the above code its showing the IndentationError, Why its occuring ? Can any one help on this ?
Sorry: IndentationError: expected an indented block (solution.py, line 3)
dhrumikansara191 In this problem constrain is specified which is 1<=n<=20. Should this be a part of code? and if yes then how?
ak1667578 n=5 for i in range(n): print(i**2)
MatheusMuriel for i in range(n): print(i * i)
_clfm_ Python 3 - clean & correct
Using a simple list comprehension, then unpacking the list to print. Let me know if you have any questions!
n = int(input()) squares = [x ** 2 for x in range(n)] print(*squares, sep="\n")
(From my HackerRank repo on GitHub.)
mananmalik1996 why do we use print(*squares, sep="\n") and not print(squares, sep="\n") what is the importance of that * ?
_clfm_ squaresis a list, so if you sayprint(squares), Python will print the list like[0, 1, 4, 9, ... ], with brackets and commas. There is only one item to print (the list), sosepdoesn't actually get printed at all, since there are no two items to "separate".print(*squares, sep="\n")uses the "unpacking" operator*to essentially pass the elements of the listsquarestoprint()as individual variables. This is equivalent to callingprint(squares[0], squares[1], squares[2], ... , sep="\n"), but is obviously preferable syntax.This is just to match the output format the challenge expects. There are other ways to print the list in that format.
Magnum26 for num in range(0, n): print(num**2)Or you can write it in a loop comprehension
[print(num**2) for num in range(0, n)]
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