SemperPeritus Solution in a single line (Python 3):
print(*range(1, int(input())+1), sep='')
anshul_13158 Can you please explain what the '*' operator is for?
Sammieo I would also like to know this.
Rusher Look for "*identifier" under https://docs.python.org/3/reference/expressions.html#calls
code_blooded__ f name == 'main': n = int(input()) for i in range(1 , n+1): print(f"{i}", end = '')
here the end = ' ' will take next iteration as the argument and print it in the same line.
patilyeshu777 i also
SemperPeritus For short operator '*' allows you to pass an array. Example:
user = [name, password, captcha]log_in(*user)sopan94 please can u explain in detail..??
willyhhsu thank you. Please, accept this gif as a thanks
Nischay_Arora Can you please tell me the source from which you learned Python?
trinadhkoya it removes the end characters like [,{,],}
JBallin I've never come across this explanation and I'm pretty sure it's overly simplistic and incorrect. Please provide references if there is any truth to this. Thanks!
vishalbty The * is actually used to unpack a iterator. *[1,2,3] mean 1 2 3
You can find the solution and detailed explanation here.
mix123 My answer, I prefer clear and simple logic ;-)
from __future__ import print_function N = int(raw_input()) for i in range(1, N+1): print(i, end="")a_yashrocky But the challenge is to write it in one line
hijamesgill Nope. The challenge is to print the output on one line.
JBallin try
N = input()
w_merc I think without going to google, and not having previous Python experience, its impossible to do this task. The tutorial is very poor.
mcclintock85 I agree. As a very green python student, I've never encountered 'end= '. I wouldn't even know how to search for it from just this problem.
[deleted] I did it, so its not impossible. It took me like an hour, but I made it. You need to know some math (positional systems to generate the number).
I have to say, reading the top solution here was humiliating.
danclayson I also solved it using math -- so much easier to do once you fully understand the
printmethod, and either usesep=orend=.That said, it's also good practice to think through how you'd solve it without features like that!
jonathanholson This is not impossible without knowing advanced python. Just use number theory:
if __name__ == '__main__': a = int(input()) # Establish value to return val = 0 # Establish exponent for adding each digit exp = 0 # Loop through digits from a to 0; add along the way for i in range(a, 0, -1): # Get digits in i, store in vals in reverse order b = i vals = [] while b > 0: vals.append(b % 10) b //= 10 # Add vals to val for j in vals: val += 10**exp * j exp += 1 print(val)
aleksey_a_ilin if name == 'main': n = int(input())
x=0 for i in range(n): x=x+((i+1)10*(n-(i+1))) print(x)# It works well but doesn't submit/ I don't know why :(
srawat2 for i in range(1,n+1): print (i, end='')
rfstahl simple and works in Python 3. Other submissions seem unnecesarily complicated
bansalayush925 but i am getting error near end what i have to do
saurabhmithe How about this approach? It passes all the test cases.
from __future__ import print_function if __name__ == '__main__': n = int(raw_input()) for i in range (1,n+1): print(i, end="")
The comma(,) after i supresses the new line and the end is the delimiter that will be used while printing (can be replaced with space for printing numbers with a single space between)
STRout it's good, we can do by this way also if name == 'main': n = int(input()) i=1 while i<=n: print(i,end="") i+=1
angelo_pereira This makes more sense than the "'*' approach" mentioned in a (very) long stream of commments here, because the Idea is to "use the print function". I'd condense it a bit:
[print(i+1, end = '') for i in range(n)]
(The "'*' approach" is way more elegant, though :))
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