Can you please explain what the '*' operator is for?

helps a lot :)

cool, never heard of the * identifier before, thanks.

What would be an alternative to this in python 2>

Thanks, better than my solution

print (''.join([str(i) for i in range(1,int(input())+1)]))

Reading through comments now, this fails the following criteria:

Without using any string methods

but i didn't get it worked in python 2 version

but i didn't get it worked in python 2 version

but i didn't get it worked in python 2 version

I ran this and it worked. My question is how does adding the asterisk to "range" make it work. im supposing that range(arg) is returned as a list so adding the asterisk unpacks the list correct?

or you can do like this

[print(i, end='') for i in range(1,int(input())+1)]

Thanks any recommendations on how to do this in Python 2?

doesnt get sep='' it reduce it by storing it?

what is the meaning of "sep''" which is last argument of your code ?

getting error in *range ,showing it as invalid syntax

One line, but less clear. I'd rather read something simple and easy to scan, like:

for x in range(1,n+1):
    print(x,end='')

Is there any similar way in python 2 too? For sure * operator is not working in python 2.

it is showing error: Sorry: IndentationError: expected an indented block (solution.py, line 2)

this for me looks like more the packing and unpacking way to receive parameters

https://hangar.runway7.net/python/packing-unpacking-arguments

I get the following error, when trying this example: Traceback (most recent call last): File "solution.py", line 5, in print(*range(1, int(input())+1), sep='') EOFError: EOF when reading a line

This is what worked for me.

for i in range (1,n+1): print(i, end='')

I never understand why people are obsessed with one liners or short answers. Beginners should strive to write understanble code, that makes sense in your mind. I'll leave link here List Comprehensions but a solution with a for loop is only two lines:

for i in range(1, n + 1):
        print(i, end="")

what is sep

Both python version using generator

print(*[n+1 for n in range(input())], sep='')

the output was a list in this case.can you explain me why? and moreover in the question the output should not be a list. thank you.

if name == 'main': n = int(input()) for i in range(n): print(i + 1, end='')

    #this might be the easiest way to solve using python 3

The solution is following: n=int(input()) print(*range(1, n+1), sep='')

Here, if we don't use *range & sep='' then the answar will be respectively range(1, 4) & 1 2 3.*range function which takes multiple input arguments & sep='' function call makes sure that there is no space between the values.

Tried this:

for a in range (1,n+1)
print(str(a))

obviously i got wrong because it printed out vertical.

then this:

print(*range(1, n+1), sep='')

Much easier to understand.

Does this method print a string as opposed to an integer?

For input =3,

print(range(1, int(input())+1), sep='')

O/p

range(1,3)

If we put *

print(*range(1, 3), sep='')

O/p

123

hey dude! what function is used in python 2 for sep='' or end=''

why we use sep=' '?

It is not working!

Can you tell, is it faster then for loop?

Good code, spent a while disecting it thanks.

your code is impreesive but i was curious in knowing that can it be done by using for loop because i was trying to do so and the i was getting : 1 2 3 . . . N please help how to do it using for loop

why are we writing sep at last?

That doesn't work

Your function and idea are perfact!

can you explain what is mean by sep=''

A simpler solution - [print(num+1, end='') for num in range(n)]

anyone pls explain about 'sep' at the end of this code

what is sep=''

could u pls explain this statement ?

Don't use this complicated method i suggest the end keyword in the print statement.

for some reason it is not working, did i miss anything

print(*range(1, int(input())+1), sep='') File "", line 1 print(*range(1, int(input())+1), sep='') ^ print(*range(1, 4),end='') File "", line 1 print(*range(1, 4),end='') ^

note this was giving a EOFError this worked print(*range(1, n+1), sep='')

This is a string method btw

for i in range(1,n+1): print(i,sep='') This is also similar to the code which you have written.But may I know why it is not working?

why sep=' '

the question is 'without any string methods'....is there a string method actually to get this solution?

In the case of python, the working of the programming section is very much easy. It makes programming easy and attractive. That is why I always like to study python Hostsailor . The programming language is having some simple syntax to handle the printing operation.

hey what it is sep =''

Thank you!

is the above one should definately have two parameters ? because ,there is no space between no's in output . is it valid if we won't write sep="" or the syantax is like that?

x = int(input()) i = 1

for i in range(i,x+1): print(i,end=''")

from future import print_function n = int(raw_input()) for i in range(1,n+1): print(i,end='')

It's mentioned that it's without using any string functionality. it should be based on number logic.

Usually single line solutions are nasty.

for x in range(1,n+1):
    print(x,end = "")

Didn't work for me, I tried as below and worked,

print(*range(1,n+1), sep='')

how to do the program for print function explain full program

explain this

wrong? invalid syntax

Thanks bro ))

But the challenge is to write it in one line

hi, can u tell me why have you used end="" in your code. thank you

try N = input()

for i in range(1, N+1)

how does this line of code work? why does it not go past N? if N=3 then it should print 12345.... what am i missing here?

This is the pythonic way of doing it. Keep it simple and explicit. Nice.

bt it is giving indentation error.

end="" doesn't work in Python 2. What else can I do?

So i by default in a for loop is interpreted as 0? Interesting.

I agree. As a very green python student, I've never encountered 'end= '. I wouldn't even know how to search for it from just this problem.

I did it, so its not impossible. It took me like an hour, but I made it. You need to know some math (positional systems to generate the number).

I have to say, reading the top solution here was humiliating.

This is not impossible without knowing advanced python. Just use number theory:

if __name__ == '__main__':
    a = int(input())

    # Establish value to return
    val = 0
    # Establish exponent for adding each digit
    exp = 0

    # Loop through digits from a to 0; add along the way
    for i in range(a, 0, -1):
        # Get digits in i, store in vals in reverse order
        b = i
        vals = []
        while b > 0:
            vals.append(b % 10)
            b //= 10
        # Add vals to val
        for j in vals:
            val += 10**exp * j
            exp += 1
    
    print(val)

it's good, we can do by this way also if name == 'main': n = int(input()) i=1 while i<=n: print(i,end="") i+=1

simple and works in Python 3. Other submissions seem unnecesarily complicated

For me ,

for i in range(1,int(input())+1): print(i,sep='')

doesnt work, but,

for i in range(1,int(input())+1): print(i,end="")

works.

I am using Python3 , anyone knows why is this happening?

not supposed to use string methods

I'm Impressed by the little logic behind :D