I would also like to know this.

For short operator '*' allows you to pass an array. Example:

user = [name, password, captcha]

log_in(*user)

it removes the end characters like [,{,],}

It is called unpacking operator.

Meaning, if you have a function which takes multiple input arguments, say func(a,b,c); instead of passing them seperately, you can pack them in a list, args = [a,b,c]; and pass this list to your function, func(*args)

And How does your function know that the received argument (args) is a packed list? It'll when you supply unpack argument '*'

Note, operator '**', when used on a dictionary, returns its keys.

Source: https://docs.python.org/2/tutorial/controlflow.html#unpacking-argument-lists

* Explanation

Python's Print Function defines the input as *objects, not as iterable like it does for Map.

An example of an iterable is a list because we can keep stepping through the elements one at a time.

print instead needs multiple arguments for each object you want to print. * is a way to "unpack" a list so that it becomes arguments instead of a list. f(*[1,2,3]) converts to f(1,2,3).

Example using print (from future in py2):

print([1,2,3])
#[1, 2, 3]

print(*[1,2,3])
#1 2 3

print(1,2,3)
#1 2 3

The last two exhibit the desired result, you just need to set sep='' to get 123 (w/o spaces).

it's for optional varied length arguments to be recieved

unpacking list i mean it converts [1,2,3] to 1,2,3 that sep = '' replaces , with blank

Its a multiplication

print (vishal*5) it will print vishal five times.

it containts the series of values:

Ex:

a = [1,2,3,4,5,6,7,8,9]
x, *y = a
print(x)
print(y)

then x will be 1 and y will be 2,3, ...,9

this is known as the "multiplication operator".

It means, all the element in the array.

n = int(raw_input()) print(*range(1,n+1), sep='',end='\n', file= sys.stdout)

*range(start, end) - ' *' meaning all the element in range() from start to ends.

range() - you can google it how it works.

Hope this helps.

Why would people down vote this so much? Gotta ask the "dumb" questions we don't answer to.

• is to print the numbers or strings sequentially in tha saem way the * is only applicable for iterating print statement after * but not to other.

it is a symbol used to remove the '[ ]' of an array such that only the values of the array will be printed

print(*[5,6])

[5,6]

print(*[5,6])

5 6

print(*[5,6],sep="")

56

*[5,6] removes brackets

• means ALL

*range used to extrect all the values from range space seprated

Everything is explained here

With * you can get the value of the range function which is calculated. If you remove * the statement "range(1, 4)" will be printed. " * " is just used to get the value.

"*" operator seems to be an unpack operator. It is used for unpacking the elements of an array. In the example posted by @SemperPeritus range() function returns an array of elements starting from 1 till N (integer we get as user input). For the print function to access each element of the array so as to print them in one line we need to unpack the array and then give it to the print function to display each element of the array seperated by the specified seperator which in above example seems to be blank ('').

print(120 + n)

Doesn't this use a string operation?

print(*range(1, int(raw_input())+1), sep='')

print(*range(1,input()+1),sep='')

you have to import the print_function and input vs. raw_input works differently in py2

from __future__ import print_function
print(*range(1,input()+1),sep='')

I just did and this worked

from __future__ import print_function
print(1,2,3,sep='')

That's correct, it unpacks the list so that they are multiple arguments (which print_function from future in py2 (or just print in py3) accepts) to print the range in succession instead of just printing a list.

I explained it in depth, above, in a couple different comments.

thanq

expalining in simple terms sep='' insert 0 space between the list items output.For example, sep='' output = 123 sep=' ' output = 1 2 3 sep='1 ' output = 11 21 31

that is sep will insert (whatever you enter in it) between the succesive elemnts of the list passed as first argument

not working

please help

thanks bro, it works in python3

This one seems more clear to understant.

what does end do here?

I totally agree with you, your answer is understandable and also short for beginners.

I agree with you

Python print function sep is a parameter for separator

Actually in Python 2, range will is NOT a generator, that only happend in Python 3. in Python 2, you would use xrange if you wanted a generator.

The default separator is a space character and, per the requirements, there shouldn't be spaces between the numbers. Thus, you manually use sep='' to override the default.

I have no idea. I'm new to this, not looking for efficiency just trying to learn.

in python if u write print(5,6) buy def. it takes " " as b/w 5 and 6 so if u diont need space u should write sep=''"

separate

sep defines the separator. Suppose you want to keep a space between the printed values then you would have to pass sep = ' '. But for this program we don't want any gap so we pass sep = '' .

Nope. The challenge is to print the output on one line.

Without 'end="" ', every number would be on next line. for example:

input:4

Output:

1

2

3

4

Expected Output: 1234

that's just how range works. play around with it. It doesn't include the last number.

print range(3)
#(0,1,2)
print range(1,3)
#(1,2)

Apparently it does if you import the print_function method like so:

from future import print_function

I also solved it using math -- so much easier to do once you fully understand the print method, and either use sep= or end=.

That said, it's also good practice to think through how you'd solve it without features like that!

The problem states that our solution must be done "Without using any string methods"