SemperPeritus Solution in a single line (Python 3):
print(*range(1, int(input())+1), sep='')
anshul_13158 Can you please explain what the '*' operator is for?
Sammieo I would also like to know this.
Rusher Look for "*identifier" under https://docs.python.org/3/reference/expressions.html#calls
sanjna_srivatsa I think it means "all". That's how we know it in SQL
daturaman [deleted]daturaman This is Python, not SQL. Read the comments below.
nyabayo45 It means 'Everything in', taking multiple args
Sanjit_Prasad * means taking everything 0 or more.
def fun(*args): total = 0 for i in args: total += i return total print(fun()) print(fun(1)) print(fun(1, 2, 3))
Callat It's a parameter for unpacking a collection. In short it says "everything in this set".
** foo is also used for dictionaries. Looking unpacking and packing keyword arguments in python 3.
It's a really cool piece of sugar.
h150303105219 its showing error: "return outside the function"
rkumar9997 use indentation
astadnik1 seems like its adding all ints together
TheSteelGuy Its works in simmilar manner to the spread operator in javascript. All it does is unpacking the content of the list
shashanksen28 - here refer taht it can contain muliple values in that arggument
navin16 oh i think it used to call
zeeshan_soccer f name == 'main': n = int(input()) for i in range(1 , n+1): print(f"{i}", end = '')
here the end = ' ' will take next iteration as the argument and print it in the same line.
amanda_shotts what is the f for? in the print statement
rabha_karishma Formated string.
sqlapouett Looks pretty unreadable. I would not do that.
SemperPeritus For short operator '*' allows you to pass an array. Example:
user = [name, password, captcha]log_in(*user)sopan94 please can u explain in detail..??
JBallin did you see my explanation below? give it an upvote if helpful. @RahulDamineni took a crack at it too. What about it do you not understand?
--
In this example given by @SemperPeritus, he's providing a function
log_inthat takesname, password, captchaas arguments.In general, you pass in arguments like so:
function(arg1,arg2,arg3)
But, if you put them in a list such as:
function([arg1,arg2,arg3])
then it's like you're only passing in 1 argument (the list) and you'll get an error saying
functionwas expecting 3 arguments and only got 1.On the other hand if you were to include
*it would "unpack" the list (imagine the list is a suitcase and the elements are pieces of clothing you want to put on the bed to look at individually. you can't do that without unpacking the suitcase, right?) so that it would still work:function(*[arg1,arg2,arg3])
becomes
function(arg1,arg2,arg3)
So
*userchanges from a list:user = [name, password, captcha]
to arguments:
*user = name, password, captcha
So now
log_inwill work without errors because it was passed 3 arguments instead of 1!
Want to learn more about a related topic in Python called
zip? Check out my blog post: medium.com/@PrintSupWorld/unzipping-python-2-340701d300a6yidingyang1027 Great interpretation!
satyakibose98 It was helpful, but can you please explain this for print(*range(1, int(input())+1), sep='')?
PS1985 n = int(input()) *range (1, n+1) = range is from 1 to n, exclusive of n. so if your input is 3 then it prints 1 2. So input to the range function is 1 to n+1
if you don't give sep='' in print statement then each value is seperated by a space
sksaravananp Thank you for the explanation. But why we need to use * range() instead of range()
vishnu_b All non-keyword arguments are converted to strings like str() does and written to the stream, separated by sep and followed by end. From printfunction doc.
So if we just give range(1, n) python3 will just print out range(1, n) since str(range(1, n)) is range(1, n).
Also read @JBallin's explanation below.
sahilkrsingh30 reading pyhton docs is a must for every solution i guess
thomasokonkwo91 wow... Nice one. Thanks man!
thomasokonkwo91 wow... Nice one. Thanks man!
ajaygiri2320 Why is this not working for me? I have written the code as below.
if name == 'main': n = int(input()) print(*range(1,n+1),sep='')
but I am getting an error msg like : Sorry: IndentationError: unindent does not match any outer indentation level (Solution.py, line 3)
Any help here please?
sqlapouett Did you write it like that?
It should be on two lines, the first line being
if name == 'main':
haloerika You mean
if __name__ == '__main__':? Anyhow, I forgot what I wrote. It is deleted somehow.
smeshram258 thanks it was very much helpful
researchers902 Superb explanation. So this will work for lists only or dictionary too ?
vishnu_b Python will unpack just the keys.
albaqawi fantastic explaination... for any new comer that needs more clarity make sure you know that you need to use n instead of int(input())
like this print(*range(1,n+1),sep='')
now as Explained by JBallen the range now is 1 to n+1 arrguments passed to the print function and the seperator is no space
Happy coding! :)
preneetdash1999 Yeah i also tried this one but is their something more cool form of coding is any fuction, is their any fuction which can do this job linke in two words. As passing objects only.
karanveermahesh1 n = int(input("")) for i in range(1,n+1): print(i, end = "")
s0rav Now this is the thing! Deserves an upvote!
greggouveia Awesome explanation @JBallin! Thanks for sharing it on such a good willing way. I'll be following youo on medium =) Keep up the good work
nksinghal41 great explanation
vdeverdu That's more or less like the spread operator '...' in javascript, right?
Tomar_Biceps '' On the other hand if you were to include * it would "unpack" the list '' Sir now if we do not provide all required arguments what will happen ? And by including * [ ] it becomes ?
poojasolai what if i want to refer to one of my arguments being passed in the function log_in? Like if i want to assign value1 = arg1 (i.e., name)
geethashree_pea1 Well explained.
miabhishekkulka1 Great! Thanks
jaswanthsai121 noo
willyhhsu thank you. Please, accept this gif as a thanks
Nischay_Arora Can you please tell me the source from which you learned Python?
rakeshdme100 Fantastic
trinadhkoya it removes the end characters like [,{,],}
JBallin I've never come across this explanation and I'm pretty sure it's overly simplistic and incorrect. Please provide references if there is any truth to this. Thanks!
RahulDamineni It is called unpacking operator.
Meaning, if you have a function which takes multiple input arguments, say func(a,b,c); instead of passing them seperately, you can pack them in a list, args = [a,b,c]; and pass this list to your function, func(*args)
And How does your function know that the received argument (args) is a packed list? It'll when you supply unpack argument '*'
Note, operator '**', when used on a dictionary, returns its keys.
Source: https://docs.python.org/2/tutorial/controlflow.html#unpacking-argument-lists
JBallin *ExplanationPython's Print Function defines the input as
*objects, not asiterablelike it does for Map.An example of an iterable is a list because we can keep stepping through the elements one at a time.
printinstead needs multiple arguments for eachobjectyou want to print.*is a way to "unpack" a list so that it becomes arguments instead of a list.f(*[1,2,3])converts tof(1,2,3).Example using
print(from future in py2):print([1,2,3]) #[1, 2, 3] print(*[1,2,3]) #1 2 3 print(1,2,3) #1 2 3
The last two exhibit the desired result, you just need to set
sep=''to get123(w/o spaces).digitalchemy Nice explanation! Just a little remark: Saying that *[1,2,3] converts to (1,2,3) is a bit misleading, becouse it suggests that it converts the list to a tuple, which for print() function beahves the same as the list.
JBallin @digitalchemy great point! I clarified that it applies to arguments inside a function call (see "f()")
ramyamuthu2101 [deleted]
sri_sam229 it's for optional varied length arguments to be recieved
g_jaswanth unpacking list i mean it converts [1,2,3] to 1,2,3 that sep = '' replaces , with blank
7dec1997 Its a multiplication
vishalit10 print (vishal*5) it will print vishal five times.
rajatjog1294 it containts the series of values:
Ex:
a = [1,2,3,4,5,6,7,8,9] x, *y = a print(x) print(y)
then x will be 1 and y will be 2,3, ...,9
lalit_chandora this is known as the "multiplication operator".
alaniane The context determines what type of operator it is. Many languages overload symbols to mean more than just one operator. For example in C:
int *ptr = &y; *ptr = 5; z = y * x;
* in the first instance declares a pointer variable
* in the second instance is called a dereference operator
* in the third instance is a multiplication operator.So, from what I can tell about the comments above in Python: What type of operator '*' is depends on its context.
*[1,2,3] the * is not the same as 2 * 3 where it is the multiplication operator.
NikolaLukic This works but still my results is 123 not 1 2 3. Who to inser spaces ?
surendran8907 It means, all the element in the array.
surendran8907 n = int(raw_input()) print(*range(1,n+1), sep='',end='\n', file= sys.stdout)
*range(start, end) - ' *' meaning all the element in range() from start to ends.
range() - you can google it how it works.
Hope this helps.
NikolaLukic Python is real defferent from others pl !
scades06 Why would people down vote this so much? Gotta ask the "dumb" questions we don't answer to.
yskchowdary4 - is to print the numbers or strings sequentially in tha saem way the * is only applicable for iterating print statement after * but not to other.
[deleted] it is a symbol used to remove the '[ ]' of an array such that only the values of the array will be printed
rkumar9997 print(*[5,6])
[5,6]
print(*[5,6])
5 6
print(*[5,6],sep="")
56
*[5,6] removes brackets
ashutoshsoni891 - means ALL
sandilya_august1 [deleted]
dvsrwt *range used to extrect all the values from range space seprated
kanha72 With * you can get the value of the range function which is calculated. If you remove * the statement "range(1, 4)" will be printed. " * " is just used to get the value.
shanhackerdev "*" operator seems to be an unpack operator. It is used for unpacking the elements of an array. In the example posted by @SemperPeritus range() function returns an array of elements starting from 1 till N (integer we get as user input). For the print function to access each element of the array so as to print them in one line we need to unpack the array and then give it to the print function to display each element of the array seperated by the specified seperator which in above example seems to be blank ('').
tarunverma008 '*' operator unpacks the values in range(1,n+1).
anujmishraeps multiply
sostomc011 from the docs, if * appears before a callable, then it evaluates to an iterable. e.g if you have function foo that evaluates to ['a,b,c] and call it here [1,2,*foo,3,4] you get 1,2,a,b,c,3,4
abhinavkushwaha1 for multiplication
yadavishal_93 i think i see the value at that address
gauravjain_cr7 hello
rosiecakes cool, never heard of the * identifier before, thanks.
local_bantai What would be an alternative to this in python 2>
surajdeshpande print(*range(1, int(raw_input())+1), sep='')
mubarakbsc123 Thanks a lot.
JBallin print(*range(1,input()+1),sep='')JBallin if this isn't working it's because you forgot to import print_function from future:
from __future__ import print_function print(*range(1,input()+1),sep='')
mikee531 what is sep=??
Joey_wen it is abbreviations of "separator"
Joey_wen I think "xrange" is better than "range",there are some difference between them.
hikinthru The question was about Python 2. Importing future essentially sets the program to Python 3. Which means it doesn't actually answer the question.
JBallin they instruct us to import from future for python 2
yuanster From https://docs.python.org/2.7/library/functions.html?highlight=print#print"
"Note This function is not normally available as a built-in since the name print is recognized as the print statement. To disable the statement and use the print() function, use this future statement at the top of your module:
from __future__ import print_function
"New in version 2.6"
(Interestingly, this is now inserted in the template when you select Python 2.) Have to say that I'm a bit surprised that Python didn't offer something like sprintf.
amirularif tq
Atikullah please explain
christokleu Thanks, better than my solution
print (''.join([str(i) for i in range(1,int(input())+1)]))
Reading through comments now, this fails the following criteria:
Without using any string methods
hacker_gf [deleted]
SANJAY5797 but i didn't get it worked in python 2 version
JBallin you have to import the
print_functionandinputvs.raw_inputworks differently in py2from __future__ import print_function print(*range(1,input()+1),sep='')
Sani1997 why the * for? new to python.. so.asked..
omavinashkalal - Explanation Python's Print Function defines the input as *objects, not as iterable like it does for Map. An example of an iterable is a list because we can keep stepping through the elements one at a time. print instead needs multiple arguments for each object you want to print. * is a way to "unpack" a list so that it becomes arguments instead of a list. *[1,2,3] converts to (1,2,3). Example using print (from future in py2): print([1,2,3])
[1, 2, 3]
print(*[1,2,3])
1 2 3
print(1,2,3)
1 2 3
The last two exhibit the desired result, you just need to set sep='' to get 123 (w/o spaces). Source: JBallin
ssarota Thank you. Import is something I was not familiar.
SANJAY5797 but i didn't get it worked in python 2 version
f0rk_b0mb I just did and this worked
from __future__ import print_function print(1,2,3,sep='')
SANJAY5797 but i didn't get it worked in python 2 version
danielbarreto557 I ran this and it worked. My question is how does adding the asterisk to "range" make it work. im supposing that range(arg) is returned as a list so adding the asterisk unpacks the list correct?
JBallin That's correct, it unpacks the list so that they are multiple arguments (which
print_functionfromfuturein py2 (or justprintin py3) accepts) to print the range in succession instead of just printing alist.I explained it in depth, above, in a couple different comments.
vikas_kr or you can do like this
[print(i, end='') for i in range(1,int(input())+1)]
SANJAY5797 thanq
john_hollwitz Thanks any recommendations on how to do this in Python 2?
harshit_thakore doesnt get sep='' it reduce it by storing it?
ajaymania12 what is the meaning of "sep''" which is last argument of your code ?
masquerade0097 expalining in simple terms sep='' insert 0 space between the list items output.For example, sep='' output = 123 sep=' ' output = 1 2 3 sep='1 ' output = 11 21 31
that is sep will insert (whatever you enter in it) between the succesive elemnts of the list passed as first argument
STMohd getting error in *range ,showing it as invalid syntax
hijamesgill One line, but less clear. I'd rather read something simple and easy to scan, like:
for x in range(1,n+1): print(x,end='')
kumarparth123 not working
kumarparth123 please help
jaffarjawed thanks bro, it works in python3
shaikotrio This one seems more clear to understant.
abhinavbahl51 what does end do here?
madhu4mobile Is there any similar way in python 2 too? For sure * operator is not working in python 2.
satyakibose98 it is showing error: Sorry: IndentationError: expected an indented block (solution.py, line 2)
lrodlima this for me looks like more the packing and unpacking way to receive parameters
https://hangar.runway7.net/python/packing-unpacking-arguments
subhadeepmaji440 [deleted]
Norse I get the following error, when trying this example: Traceback (most recent call last): File "solution.py", line 5, in print(*range(1, int(input())+1), sep='') EOFError: EOF when reading a line
vaisakhsrinivas This is what worked for me.
for i in range (1,n+1): print(i, end='')
ic3balandran I never understand why people are obsessed with one liners or short answers. Beginners should strive to write understanble code, that makes sense in your mind. I'll leave link here List Comprehensions but a solution with a for loop is only two lines:
for i in range(1, n + 1): print(i, end="")
www_shreyanshda1 what is sep
dimithras Python print function sep is a parameter for separator
sai4ever the output was a list in this case.can you explain me why? and moreover in the question the output should not be a list. thank you.
bad_coder_lol if name == 'main': n = int(input()) for i in range(n): print(i + 1, end='')
#this might be the easiest way to solve using python 3shampa1 The solution is following: n=int(input()) print(*range(1, n+1), sep='')
Here, if we don't use *range & sep='' then the answar will be respectively range(1, 4) & 1 2 3.*range function which takes multiple input arguments & sep='' function call makes sure that there is no space between the values.
emrepallamut Tried this:
for a in range (1,n+1) print(str(a))
obviously i got wrong because it printed out vertical.
then this:
print(*range(1, n+1), sep='')
Much easier to understand.
mstevenbowen Does this method print a string as opposed to an integer?
chiragckarkera For input =3,
print(range(1, int(input())+1), sep='')
O/p
range(1,3)
If we put *
print(*range(1, 3), sep='')
O/p
123
ss_sariana hey dude! what function is used in python 2 for sep='' or end=''
abhisheksingh39 why we use sep=' '?
tomada36 The default separator is a space character and, per the requirements, there shouldn't be spaces between the numbers. Thus, you manually use sep='' to override the default.
janu_s It is not working!
tomada36 [deleted]piyush1751995 Can you tell, is it faster then for loop?
scades06 I have no idea. I'm new to this, not looking for efficiency just trying to learn.
piyush1751995 Cool man, thks for responding. No problem. By the way I think it is same as for loop
Asura0789 Good code, spent a while disecting it thanks.
venuk396 your code is impreesive but i was curious in knowing that can it be done by using for loop because i was trying to do so and the i was getting : 1 2 3 . . . N please help how to do it using for loop
vyshnavisank81 why are we writing sep at last?
holloway_lerena That doesn't work
ZhangXiaofanfan Your function and idea are perfact!
deepika121 [deleted]kishorjanwade12 can you explain what is mean by sep=''
rkumar9997 in python if u write print(5,6) buy def. it takes " " as b/w 5 and 6 so if u diont need space u should write sep=''"
separate
salmanashahab [deleted]
maleficent A simpler solution - [print(num+1, end='') for num in range(n)]
kenjihikmatullah anyone pls explain about 'sep' at the end of this code
vammu920 what is sep=''
sarathkumar904 could u pls explain this statement ?
khush_upadhyay Don't use this complicated method i suggest the end keyword in the print statement.
msrajanadar for some reason it is not working, did i miss anything
print(*range(1, int(input())+1), sep='') File "", line 1 print(*range(1, int(input())+1), sep='') ^ print(*range(1, 4),end='') File "", line 1 print(*range(1, 4),end='') ^
AK0000000 note this was giving a EOFError this worked print(*range(1, n+1), sep='')
abhishekugale911 This is a string method btw
160216737070_IT for i in range(1,n+1): print(i,sep='') This is also similar to the code which you have written.But may I know why it is not working?
amabirbd [deleted]pathak_harshit why sep=' '
amabirbd sep defines the separator. Suppose you want to keep a space between the printed values then you would have to pass sep = ' '. But for this program we don't want any gap so we pass sep = '' .
pathak_harshit thanks :)
anji_praji [deleted]praneeth_vvs the question is 'without any string methods'....is there a string method actually to get this solution?
isabelladom247 In the case of python, the working of the programming section is very much easy. It makes programming easy and attractive. That is why I always like to study python Hostsailor . The programming language is having some simple syntax to handle the printing operation.
rahulkumargoyal1 hey what it is sep =''
pathak_harshit Its a seperator....to find space between characters... for eg between a string
kavithamidde888 Thank you!
meghanavaitla201 is the above one should definately have two parameters ? because ,there is no space between no's in output . is it valid if we won't write sep="" or the syantax is like that?
kavithamidde888 Thank you
stevencnix [deleted]srinivasvl_vaya1 x = int(input()) i = 1
for i in range(i,x+1): print(i,end=''")
rayiya313 from future import print_function n = int(raw_input()) for i in range(1,n+1): print(i,end='')
mikhil_nagarale It's mentioned that it's without using any string functionality. it should be based on number logic.
haloerika [deleted]gundoganfa Usually single line solutions are nasty.
nikhilsonimlv for x in range(1,n+1): print(x,end = "")
IshworBhusal Didn't work for me, I tried as below and worked,
print(*range(1,n+1), sep='')
nikhilsonimlv did you try by selecting "PYTHON 3" into editor? because it worked for
IshworBhusal Yes, I tried on Python 3 itself, but didn't work initially, later with some indentization and some other slight modifications, it worked. Thank you Nilkhil!
kondravarunkumar how to do the program for print function explain full program
gbr8214 explain this
mix123 My answer, I prefer clear and simple logic ;-)
from __future__ import print_function N = int(raw_input()) for i in range(1, N+1): print(i, end="")a_yashrocky But the challenge is to write it in one line
hijamesgill Nope. The challenge is to print the output on one line.
JBallin try
N = input()
Supreme_One for i in range(1, N+1)
how does this line of code work? why does it not go past N? if N=3 then it should print 12345.... what am i missing here?
JBallin that's just how
rangeworks. play around with it. It doesn't include the last number.print range(3) #(0,1,2) print range(1,3) #(1,2)
Supreme_One i understand that, but, range(start, stop) so if you have n=3 and range is range(1, n+1) wouldnt that mean that n=1 then n=2 etc, because of the n+1 wouldnt it just keep going past 3 to 4, 5, 6, 7....infinite loop?
nevermind i figured it out writing this post, lol. thanks!
Supreme_One i was thinking of n+=1 which would make n=4, 5, 6 and so on. the range function being used is range(1, n+1) making it range(2, n+1)....and so on. correct me if im wrong.
JBallin rangeproduces alistand it doesn't change once it's produced.I made a mistake above, it
prints out alist([]instead of()) becauserangeis just a way to make alist:print range(3) #[0,1,2] type(range(3)) #<type> 'list' range(3) == [0,1,2] #True
n = 3 print range(1,n+1) #[1,2,3]
Next the code goes through the
list(range(1,4)=[1,2,3]), element by element, and prints each number. It first prints 1, then 2, then 3. It doesn't go to the next line bcend=''and insteadprints them next to each other.Make sense?
JBallin It calculates
rangeonce, and keeps referring back to the samelist.
sagar10451 in for loop that we use i is incremented and not the range. range is fixed it gives order to for loop i to go till itd range is given and i start from lower value to higher in higher value of range. hope this helps!!
MakoShark This is the pythonic way of doing it. Keep it simple and explicit. Nice.
satyakibose98 bt it is giving indentation error.
Bhagya_Gaikwad end="" doesn't work in Python 2. What else can I do?
TytoCorvus Apparently it does if you import the print_function method like so:
from future import print_function
chefyunfei So i by default in a for loop is interpreted as 0? Interesting.
w_merc I think without going to google, and not having previous Python experience, its impossible to do this task. The tutorial is very poor.
mcclintock85 I agree. As a very green python student, I've never encountered 'end= '. I wouldn't even know how to search for it from just this problem.
flappo_ramiro I did it, so its not impossible. It took me like an hour, but I made it. You need to know some math (positional systems to generate the number).
I have to say, reading the top solution here was humiliating.
danclayson I also solved it using math -- so much easier to do once you fully understand the
printmethod, and either usesep=orend=.That said, it's also good practice to think through how you'd solve it without features like that!
jonathanholson This is not impossible without knowing advanced python. Just use number theory:
if __name__ == '__main__': a = int(input()) # Establish value to return val = 0 # Establish exponent for adding each digit exp = 0 # Loop through digits from a to 0; add along the way for i in range(a, 0, -1): # Get digits in i, store in vals in reverse order b = i vals = [] while b > 0: vals.append(b % 10) b //= 10 # Add vals to val for j in vals: val += 10**exp * j exp += 1 print(val)
saurabhmithe How about this approach? It passes all the test cases.
from __future__ import print_function if __name__ == '__main__': n = int(raw_input()) for i in range (1,n+1): print(i, end="")
The comma(,) after i supresses the new line and the end is the delimiter that will be used while printing (can be replaced with space for printing numbers with a single space between)
STRout it's good, we can do by this way also if name == 'main': n = int(input()) i=1 while i<=n: print(i,end="") i+=1
marinskiy Here is Python solution from my HackerrankPractice repository:
for i in range(1, int(input()) + 1): print(i, sep='')
Feel free to ask if you have any questions :)
Ankita0005 For me ,
for i in range(1,int(input())+1): print(i,sep='')
doesnt work, but,
for i in range(1,int(input())+1): print(i,end="")
works.
I am using Python3 , anyone knows why is this happening?
skybird_cse09 The print function uses sep to separate the arguments, and end after the last argument. https://stackoverflow.com/questions/36513028/what-are-the-difference-between-sep-and-end-in-print-function/36513086#36513086
15A31A0572 for i in range(1,n+1): print(i,end="")
this is my solution and it passed all test cases
chaitanya_14795 print ('').join(str(i+1) for i in range(int(raw_input())))
JBallin not supposed to use string methods
SuperSoyans I'm Impressed by the little logic behind :D
imadnazim Try this:
x=range(n)
for i in x:
print(i+1,end="")
yanxiusi720 if __name__ == '__main__': n = int(input()) res=0 j=1 for i in range(0,n+1): if i==10**j: j=j+1 res=res*10**j+i print (res)
flappo_ramiro [deleted]
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