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  1. Prepare
  2. Python
  3. Strings
  4. String Formatting
  5. Discussions

String Formatting

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1775 Discussions

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  • roshankujurcare1
     + 0 comments

    This is my solution - def print_formatted(number): length = len(bin(number)[2:]) for num in range(1,number+1): print(str(num).rjust(length), oct(num)[2:].rjust(length),
    hex(num).upper()[2:].rjust(length), bin(num)[2:].rjust(length))

  • pradeepkumarbc11
     + 0 comments

    def print_formatted(number): width = len(bin(number)[2:]) for i in range(1, number+1): deci = str(i) bina = bin(i)[2:] octa = oct(i)[2:] hexa = hex(i)[2:].upper() print(deci.rjust(width), octa.rjust(width), hexa.rjust(width), bina.rjust(width))

    if name == 'main': n = int(input()) print_formatted(n) `

  • pradeepkumarbc11
     + 0 comments

    def print_formatted(number): width = len(bin(number)[2:]) for i in range(1, number+1): deci = str(i) bina = bin(i)[2:] octa = oct(i)[2:] hexa = hex(i)[2:].upper() print(deci.rjust(width), octa.rjust(width), hexa.rjust(width), bina.rjust(width))

    if name == 'main': n = int(input()) print_formatted(n)

  • danmodan92
     + 0 comments
    length_binary_column = len(f"{number:b}")
rjust = lambda s: s.rjust(length_binary_column)

for i in range(1, number + 1):
    print(
        rjust(f"{i:d}"), 
        rjust(f"{i:o}"), 
        rjust(f"{i:X}"), 
        rjust(f"{i:b}"), 
        sep=" "
    )

  • gaikwadprathame1
     + 0 comments
    def print_formatted(number):
  w = len(f"{number:b}")
  for each in range(1, number+1):
    print(f"{each:d}".rjust(w),
          f"{each:o}".rjust(w),
          f"{each:x}".upper().rjust(w),
          f"{each:b}".rjust(w))

if __name__ == "__main__":
  n = int(input())
  print_formatted(n)