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    python solution:

    query =[]
    number_of_queries = int(input())
    for q in range(number_of_queries):
        operation = input().split()
        if len(operation) == 2:
            query.append(operation[1])
        elif len(operation) == 1 and operation[0] != '3':
            query.remove(query[0])
        elif operation[0] == '3':
            print(query[0])