import re
k = []
for i in re.finditer(r'(?<=[QWRTYPSDFGHJKLZXCVBNMqwrtypsdfghjklzxcvbnm])([aeiouAEIOU]{2,})(?=[QWRTYPSDFGHJKLZXCVBNMqwrtypsdfghjklzxcvbnm])', input()):
    print(i.group())
    k.append(i.group())
if k == []:
    print(-1)

import re
S = input()
p = r'(?<=[bcdfghjklmnpqrstvwxtyzBCDFGHKLMNPQRSTVWXYZ])([aeiouAEIOU]{2,})(?=[bcdfghjklmnpqrstvwxtyzBCDFGHKLMNPQRSTVWXYZ])'

if re.findall(p,S):
    print(*re.findall(p,S), sep = "\n")
else :
    print(-1)

import re
pattern= re.compile(r'(?<=[qwrtypsdfghjklzxcvbnm])[aeiou]{2,}(?=[qwrtypsdfghjklzxcvbnm])',re.IGNORECASE)
matches= re.findall(pattern, input())
[print(*matches,sep="\n") if matches else print(-1)]

import re

pattern = '(?<=[^aeiou\s\d\W_])([aeiou]{2,})(?=[^aeiou\s\d\W_])'
lst = re.findall(rf'{pattern}', input(), re.IGNORECASE)
if lst:
    print(*lst, sep='\n')
else:
    print(-1)

import re

pattern = re.compile(r"(?<=[qwrtypsdfghjklzxcvbnm])([aeiou]{2,})(?=[qwrtypsdfghjklzxcvbnm])", re.I)
m = re.findall(pattern,input())
if m:
    print("\n".join(m))
else:
    print(-1)