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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Re.findall() & Re.finditer()
  5. Discussions

Re.findall() & Re.finditer()

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381 Discussions

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  • obianujuofodu
     + 0 comments

    import re pattern= r"(?<=[^AEIOUaeiou])([AEIOUaeiou]{2,})(?=[^AEIOUaeiou])"

    S = re.findall(pattern, input())

    if S: print(*S, sep="\n")

    else: print(-1)

  • obianujuofodu
     + 0 comments

    import re

    pattern= r"(?<=[^AEIOUaeiou])([AEIOUaeiou]{2,})(?=[^AEIOUaeiou])" S = list(re.finditer(pattern, input()))

    if S: for i in S: print(i.group())

    else: print(-1)

  • dheenupriya2001
     + 0 comments
    import re
s = input()
pattern = r'(?<=[^aeiouAEIOU])([aeiouAEIOU]{2,})(?=[^aeiouAEIOU])'
matches = re.findall(pattern, s)

if matches:
    print(*matches, sep='\n')
else:
    print(-1)

  • finndemoncat
     + 0 comments

    In case you are having issues like me to check if the iterator it's empty with the solutions here:

    import re
matches = re.finditer(r"(?<=[^aeiouAEIOU])([aeiouAEIOU]{2,})(?=[^aeiouAEIOU])", input())
found = False

for word in matches:
    print(word.group(1))
    found = True
if(not found):
    print(-1)

  • rubinaParveen
     + 0 comments
    import re 
S = input().strip()
m = re.findall(r"(?i)(?<=[^aeiou])([aeiou]{2,})(?=[^aeiou])", S)
if m: 
    print("\n".join(m))
else:
    print(-1)