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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Group(), Groups() & Groupdict()
  5. Discussions

Group(), Groups() & Groupdict()

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  • thainguyen2893
     + 0 comments
    import re
m = re.match(r'.*?([^\W_])\1.*', input())
print(m.group(1) if m else -1)

  • iamayushbhadola
     + 0 comments

    My solution in Python 3:

    import re
 
text = input()
pattern = r'(\w(?!_))\1+'
m = re.findall(pattern, text)

print(m[0] if len(m)!=0 else -1)

    With this solution we can keep a track on any 'nth' occurrence of the repeating character and can access it from list variable 'm' based on its index number.

  • abhishekk962
     + 0 comments
    import re
s = re.search(r"([a-zA-Z0-9])(\1)", input())
print(s.group(0)[0] if s else -1)

  • tkotresh3
     + 1 comment

    1.match = re.search(r'(\w)\1', s) 2.match = re.search(r'([a-zA-Z0-9])\1', s) Any idea why 1st is not a correct solution. since by definition: \w alphanumeric: [0-9a-zA-Z_] and includes "_" .

  • van00972756
     + 0 comments
    import re
pattern = re.compile(r'([a-zA-Z0-9])\1{1,}')
match=re.search(pattern,input())
print(match.group(1) if match else -1)
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