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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Group(), Groups() & Groupdict()
  5. Discussions

Group(), Groups() & Groupdict()

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254 Discussions

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  • singhshrajan
     + 0 comments

    import re

    ser = re.search(r'([a-zA-Z0-9])\1',input()) if ser: print(ser.group()[0]) else: print(-1)

  • singhshrajan
     + 0 comments
    1. import re
      1. ser = re.search(r'([a-zA-Z0-9])\1',input())
    3. if ser:
    4. print(ser.group()[0])
    5. else:
    6. print(-1)

  • singhshrajan
     + 0 comments
    1. n = input()
    2. li = "1234567890abcdefghijkelmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
    3. for i in range(len(n)-1):
    4. if n[i]==n[i+1] and n[i] in li :
    5. print(n[i])
    6. break
    7. else:
    8. print(-1)

  • pcblack777ff
     + 0 comments
    • inpt = input()
    • l = []
    • res = []
    • p = []
    • last = []
    • for i in inpt:
    • if i.isalnum():
    • l.append(i)
    • for i in range(len(l)-1):
    • if l[i] == l[i+1]:
    • res.append(i)
    • res = list(map(str,res))
    • for rev in res:
    • b = reversed(rev)
    • p.append(''.join(b))
    • for i in range(len(res)-1):
    • if res[i] == p[i]:
    • last.append(res[i])
    • if len(last) >0:
    • print(last[0][0])
    • elif len(last) == 0:
    • print(-1)
      • *

  • babafun
     + 0 comments
    import re
print((m := re.search(r"([a-zA-Z0-9])\1", input())) and m.group(1) or -1)