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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Re.start() & Re.end()
  5. Discussions

Re.start() & Re.end()

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354 Discussions

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  • nimranimra71064
     + 0 comments

    result

  • finndemoncat
     + 0 comments

    My solution:

    import re

string = input()
sample = input()
matches = list(re.finditer(rf"(?={sample})", string))

if (matches == []):
    print((-1, -1))
for word in matches:
    print(tuple((word.start(), word.start() + len(sample) - 1 )))

  • dilajevolves
     + 0 comments
    import re
S,k = input().strip(),input().strip()
print(*([(m.start(1), m.end(1)-1) for m in re.finditer(r'(?=(' + re.escape(k) + r'))',S)] or [(-1, -1)]),sep='\n')

  • tusharvyavahare1
     + 0 comments
    import re
s=input()
k=input()
flag=False
for i in re.finditer(rf'(?=({k}))',s):
    #print(i.group(1))
    print((i.start(1),i.end(1)-1))
    flag=True
if not flag:
    print((-1,-1))

  • mohamedhari317
     + 0 comments
    import re

s = input()
k = input()
regex_pattern =  r'(?={})'.format(re.escape(k))


l=list(re.finditer(regex_pattern,s))
if l==[]:
    print((-1,-1))
else:
    for match in l:
        print((match.start(),match.start()+len(k)-1))