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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Re.start() & Re.end()
  5. Discussions

Re.start() & Re.end()

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331 Discussions

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  • n4m774r_d
     + 0 comments
    import re
s,k = [input() for _ in range(2)]
p = r'(?=(%s))' % re.escape(k)
print("\n".join("(%s, %s)"%(match.start(1),match.end(1)-1) for match in re.finditer(p, s)) or "(-1, -1)")

  • kgkeklikci
     + 0 comments
    import re

string = input()
k = input()

pattern = f"(?=({k}))"
matches = re.finditer(pattern, string)
indices = []

for match in matches:
    indices.append((match.start(), match.start() + len(k) - 1))

if not indices:
    print((-1, -1))
else:
    for x in indices:
        print(x)

  • lstlst200
     + 0 comments

    ` import re

    s = input().strip() k = input().strip()

    found = False

    for match in re.finditer(r'(?=('+re.escape(k)+'))', s): found = True start_index = match.start(1) end_index = match.end(1) - 1 print((start_index, end_index))

    if not found: print((-1, -1))

    if not found: print((-1, -1))

  • ricardoandreh
     + 0 comments
    import re

s, k = input(), input()

idx = [(m.start(1), m.end(1) -1) for m in re.finditer(fr"(?=({k}))", s)]

print(*idx or [(-1, -1)], sep="\n")

  • pachosoft
     + 0 comments
    import re

s = input()
k = input()

result = [(i.start(),i.end()+len(k)-1) for i in re.finditer('(?={0})'.format(k), s)]
if len(result) > 0:
    for n in result:
        print(n)
else:
    print((-1,-1))