n = int(input()) pattern = r'(?<= )(&&|||)(?= )' for _ in range(n): a = input() s = re.sub(pattern, lambda m: 'and' if m.group(0) == '&&' else 'or',a) print(s)

Here is HackerRank Regex Substitution in Python solution - https://programmingoneonone.com/hackerrank-regex-substitution-solution-in-python.html

and_pattern = "(?<= )\&\&(?= )" or_pattern = "(?<= )||(?= )"

Explanation: (?<= ) is a look behind positive. This ensures the characters are preceeded by a space. (?= ) is a look ahead positive. This ensures the characters are followed by a space. Finally, the string in question contains characters which themselves are used in regex statement, so they must be escaped with a backslash to be recognized!

import re

def replace_operators(text): text = re.sub(r'(?<=\s)||(?=\s)', 'or', text) text = re.sub(r'(?<=\s)&&(?=\s)', 'and', text) return text

N = int(input()) text = "\n".join(input() for _ in range(N)) result = replace_operators(text) print(result)

1. import re
2. 3. for i in range(int(input())):
3. i = input()
4. i=re.sub(r"(?<= )&&(?= )","and",i)
5. i=re.sub(r"(?<= )||(?= )","or",i)
6. print(i)