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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Regex Substitution
  5. Discussions

Regex Substitution

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304 Discussions

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  • qvbich
     + 0 comments

    import re

    def replace_operators(text): text = re.sub(r'(?<=\s)||(?=\s)', 'or', text) text = re.sub(r'(?<=\s)&&(?=\s)', 'and', text) return text

    N = int(input()) text = "\n".join(input() for _ in range(N)) result = replace_operators(text) print(result)

  • singhshrajan
     + 0 comments
    1. import re
      1. for i in range(int(input())):
    3. i = input()
    4. i=re.sub(r"(?<= )&&(?= )","and",i)
    5. i=re.sub(r"(?<= )||(?= )","or",i)
    6. print(i)

  • cam_martin0505
     + 0 comments

    import re and_pattern = re.compile( r"(?<=[\s])[&&]{2}(?=[\s])" ) or_pattern = re.compile( r"(?<=[\s])[||]{2}(?=[\s])" )

    for _ in range(int(input())): print( re.sub(and_pattern,'and', re.sub(or_pattern, 'or', input())) )

    Could reduce it down, however it would make it less readable.

    Sometimes fewer lines isn't better

  • illya_muravsky
     + 0 comments
    import re
N = int(input())
text = "\n".join(input() for _ in range(N))
print(re.sub(r'(?<=\s)&&(?=\s)', 'and', re.sub(r'(?<=\s)\|\|(?=\s)', 'or', text)))

  • loucifsk
     + 0 comments
    import os, sys, re

text = sys.stdin.read()
pattern = r"(?<=\s)(&{2}|[|]{2})(?=\s)"

def modified_match(match_object):

    if match_object.group() == '&&':
        return 'and'
    else:
        return 'or'

text = re.sub(pattern, modified_match, text)
print(os.linesep.join(text.splitlines()[1:])) #removes the line count at line n°1