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  1. Prepare
  2. Mathematics
  3. Geometry
  4. Rectangular Game
  5. Discussions

Rectangular Game

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42 Discussions

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  • gschoen
     + 0 comments

    The number of squares with the highest 'x' count may exceed the range of a 32 bit integer so use long variables instead.

  • pulsar_sx21
     + 0 comments

    def solve(steps): # Write your code here first = True for i in steps: if first: minrow = i[0] mincol = i[1] first = False else: if i[0] < minrow: minrow = i[0] if i[1] < mincol: mincol = i[1] return (minrow * mincol)

  • danielbrito
     + 1 comment

    In Kotlin, I got an overflow error in some test cases. I needed to change the return type for Long to make it pass.

  • sickfortea
     + 0 comments
    #include <iostream>
using namespace std;
void rectangularGame(int n)
{
    unsigned long long int a,b, minA, minB;
    for(int i=0; i<n; i++)
    {
        cin>>a>>b;
        if(i==0)
        {
            minA=a;
            minB=b;
        }
        if(a<minA)
        {
            minA=a;
        }
        if(b<minB)
        {
            minB=b;
        }
    }
    cout<<minA*minB;
}
int main()
{
    int n;
    cin>>n;
    rectangularGame(n);
    return 0;
}

  • sri555abhi
     + 0 comments

    Java :

    import java.util.Scanner;

public class Solution {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int a = Integer.MAX_VALUE, b = Integer.MAX_VALUE;
        while (n-- > 0) {
            a = Math.min(a, sc.nextInt());
            b = Math.min(b, sc.nextInt());
        }
        
        System.out.println(1L * a * b);
    }
}