Discussion on Repeated String Challenge

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4 days ago+ 0 comments

Swift resolution

var characters = Array(s)
    
    if n == 1 {
        return s.filter({ $0 == "a" }).count
    } else if s == "a" {
        return n
    } else {
        var count = s.filter({ $0 == "a" }).count * Int(n / s.count)
        var remining = characters[0..<(n % s.count)].filter({ $0 == "a" }).count
        return count + remining
    }

5 days ago+ 0 comments

def repeatedString(s, n):
    m = len(s)
    return n//m * s.count('a') + s.count('a', 0, n%m)

5 days ago+ 0 comments

Python 3:

def repeatedString(s, n):
    full_strings = s.count('a') * (n // len(s))
    last_string = s[:n % len(s)]
    if last_string == '':
        return full_strings       
    return full_strings + last_string.count('a')

6 days ago+ 0 comments

public static long repeatedString(String s, long n) {
    // Write your code here
    long countOfFullStringRepition = n / s.length();
    long lastStringLength = n % s.length();

    long countOfAInProvidedString = s.chars().filter(character -> character == 'a').count();
    long countOfAUntilLastString = countOfAInProvidedString * countOfFullStringRepition;
    long countOfAInLastString = s.substring(0, (int)lastStringLength).chars().filter(character -> character == 'a').count();

    return countOfAUntilLastString + countOfAInLastString;
}

6 days ago+ 0 comments

def repeatedString(s, n):
    res=s.count('a')*(n//len(s))
    res+=s[:n%len((s))].count('a')
    return res

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