function reverse(llist) { var node = null; while(llist != null) { var temp = node; node = new SinglyLinkedListNode(llist.data,temp) node.next = temp llist = llist.next } return node

}

javascript solution:

` function reverse(llist) { let prev, next = null;

while (llist !== null) {
    [next, llist.next] = [llist.next, prev];
    [prev, llist] = [llist, next];
}

return prev;

} `

Great approach! Reversing a singly linked list by inserting nodes at the beginning of a new list is efficient and clean. This function is especially useful in coding interviews and beginner data structure practice.

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My python solution :

def reverse(llist):
    llist_2 = SinglyLinkedList()
    current = llist
    while current :
        node = SinglyLinkedListNode(current.data)
        node.next = llist_2.head
        llist_2.head = node
        current = current.next
    return llist_2.head

My Java solution:

public static SinglyLinkedListNode reverse(SinglyLinkedListNode llist) {
        SinglyLinkedListNode reverseList = null;
        SinglyLinkedListNode current = llist;
        
        while (current != null) {
            SinglyLinkedListNode temp = new SinglyLinkedListNode(current.data);
            temp.next = reverseList;
            reverseList = temp;
            current = current.next;
        }
        
        return reverseList;
    }