Saw a lot of code that prints the array just in reverse which is a perfect solution for this problem. If you want to actually reverse the array in your code and use it further I implemented the reversal with a xor swap. This way you don't need a temporary array or variable.

include

include

int main() { int num, arr, i; scanf("%d", &num); arr = (int) malloc(num * sizeof(int)); for(i = 0; i < num; i++) { scanf("%d", arr + i); }

/* Write the logic to reverse the array. */

// reverse array using xor swap
for(i = 0; i < num / 2; i++) {
    // implement xor swap
    // a, b
    // a = a^b
    // b = a^b
    // a = a^b
    // a and b values are swapped
    arr[i] = arr[i] ^ arr[num - i - 1];
    arr[num - i - 1] = arr[i] ^ arr[num - i - 1];
    arr[i] = arr[i] ^ arr[num - i - 1];
    }


for(i = 0; i < num; i++)
    printf("%d ", *(arr + i));

free(arr);

return 0;

}

finally done something on my own `

include

include

int main() { int i, j, num; scanf("%d", &num);

// Dynamic memory allocation
int *arr = (int *)malloc(num * sizeof(int));

for(i = 0; i < num; i++) {
    scanf("%d", &arr[i]);
}

for(j = num - 1; j >= 0; j--) {
    printf("%d ", arr[j]);
}

free(arr);

return 0;

}

Here is Array Reversal in c problem solution - https://programmingoneonone.com/hackerrank-array-reversal-solution-in-c.html

include

include

int main(){

    int n;

scanf("%d", &n);

    int arr[n];

    for(int i = 0; i < n; i++){

         scanf("%d", &arr[i]);

    }

    for(int i = n-1; i >= 0 ; i--){

            printf("%d ", arr[i]);
}
return 0;

}