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  1. Prepare
  2. C
  3. Arrays and Strings
  4. Array Reversal
  5. Discussions

Array Reversal

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844 Discussions

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  • vincentkho10
     + 0 comments
    int main()
{
    int num, *arr, i;
    scanf("%d", &num);
    arr = (int*) malloc(num * sizeof(int));
    for(i = 0; i < num; i++) {
        scanf("%d", arr + i);
    }


    /* Write the logic to reverse the array. */
    int temp;
    for(i=num-1;i>=num/2;i--){
        temp = *(arr+((num-1)-i));
        *(arr+((num-1)-i)) = *(arr+i);
        *(arr + i) = temp;
    }
    
    for(i = 0; i < num; i++)
        printf("%d ", *(arr + i));
    return 0;
}

  • sahidzack61
     + 0 comments

    include

    include

    int main(){

        int n;

scanf("%d", &n);

    int arr[n];

    for(int i = 0; i < n; i++){

         scanf("%d", &arr[i]);

    }

    for(int i = n-1; i >= 0 ; i--){

            printf("%d ", arr[i]);
}
return 0;

    }

  • nhathuy2745
     + 0 comments

    include

    include

    int main() { int num, arr, i; scanf("%d", &num); arr = (int) malloc(num * sizeof(int)); for(i = 0; i < num; i++) { scanf("%d", arr + i); }

    int *arr2 = (int*)malloc(num*sizeof(int));
/* Write the logic to reverse the array. */
for(int i = 0; i < num; i++) {
    arr2[i] = arr[num-i-1];
}
for(int i = 0; i < num; i++) {
    arr[i] = arr2[i];
}
for(i = 0; i < num; i++)
    printf("%d ", *(arr + i));
    free(arr2);
return 0;

    }

  • Kjosuephilippe
     + 0 comments
    for( int i =0, j=num-1; i<j; i++, j-- ){
        int valtemp =arr[i];
        arr[i]=arr[j];
        arr[j]= valtemp;     
       
    }

  • lukasdv2015
     + 0 comments

    I just modified the already made code...

    Changed the logic of scanning inputs to store values at the end of the array instead of at the start

    scanf("%d", &arr[num - (i + 1)])