from collections import deque # makes everything easy

if name == 'main': t = int(input().strip()) for _ in range(t): first_multiple_input = input().rstrip().split() n = int(first_multiple_input[0]) k = int(first_multiple_input[1]) d=deque([i for i in range(n)]) l=[] while len(d)>1: l.append(d.pop()) l.append(d.popleft()) if len(d)==1: l.append(d.pop()) print(l.index(k))

Question for you all

Any input would be greatly appreciated. I am wondering why I am getting this answer wrong. I identified the patterns and found that even positions decrease as the series goes on and the odd positions decrease. I built a loop to make make a new string that stores the reversing of the numbers. Then I only look for the index of the string containing k.

When I text it with the example zero it works. I have also done it with other manual examples and it seems to work fine. Not sure why it marks every other example as incorrect ` if name == 'main': t = int(input().strip()) for _ in range(t): # Loop t times first_multiple_input = input().rstrip().split()

    n = int(first_multiple_input[0])

    k = int(first_multiple_input[1])
    result_string = ""
    high = n - 1
    low = 0
    for i in range(n):
        if i % 2 == 0:  # Even index: use the high value
            result_string += str(high)
            high -= 1
        else:  # Odd index: use the low value
            result_string += str(low)
            low += 1

    index = result_string.index(str(k))  # Find the index of K as a string
    print(index)    

Is this broken? The Solution code only brings in the first test case. The T variable tells me there should be 2 cases but only one value for N and K come in. Is there something I need to do to get all the test cases?

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!/bin/python3

import math import os import random import re import sys

if name == 'main': t = int(input().strip())

for i in range(t):
    first_multiple_input = input().rstrip().split()
    n = int(first_multiple_input[0])
    k = int(first_multiple_input[1])
    L = []
    L1 = []
    for i in range(n):
        L.append(i)
    l = 0
    r = n-1
    while l<r:
        L1.append(L[r])
        L1.append(L[l])
        l += 1
        r -= 1
    if l == r:
        L1.append(L[l])
    print(L1.index(k))