Total possible outcomes from 1 die is 6. So, for both dice total possible outcome count is 6*6=36

And Following are the only pairs from those 36 cominations in which sum is not atmost 9 basically for all these combinations sum is more than 9. (4,6), (5,5), (5,6), (6,4), (6,5), (6,6)

each die has 6 sides so, total outcome=6*6=36 number of combinations are: 30

30/36 =5/6

check all possible pairs (total 36 pairs) in that only (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) will not satisfiy atmost 9 (6 pairs) so 36-6=30 prob=30/36=5/6

ans=5/6

check all possible pairs (total 36 pairs) in that only (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) will not satisfiy atmost 9 (6 pairs) so 36-6=30 prob=30/36=5/6

ans=5/6

I kept getting it wrong because I kept forgetting to add the 9s. I was adding only the numbers less than 9