Day 8: Pearson Correlation Coefficient II

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    Step 1: Rewrite the 2 lines in proper form

    Rewrite the 2 lines as:

    y = -2 + (-3/4) * x
    x = -7/4 + (-3/4) * y

    so b1 = -3/4 and b2 = -3/4

    Step 2: Apply Pearson's Coefficient formula

    Let p = pearson coefficient
    Let x_std = standard deviation of x
    Let y_std = standard deviation of y

    From this tutorial we have:

    p = b1 (x_std / y_std)
    p = b2 (y_std / x_std)

    Multiplying these 2 equations together we get
    p^2 = b1 * b2
    p^2 = (-3/4) * (-3/4)
    p^2 = 9/16
    p = 3/4 or -3/4 (depending on correlation of x and y)

    Step 3: Find out if p is postive or negative

    Notice that both of the original line equations have negative slopes, so x and y are negatively correlated by definition. So, p = -3/4

    From my HackerRank solutions.